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EleoNora [17]
3 years ago
15

OFFERING BRAINLIEST !! Using the formula, compute the true annual interest rate to the nearest tenth.

Mathematics
2 answers:
garik1379 [7]3 years ago
7 0

Answer:

Step-by-step explanation:

5x12=60

(227.5x5x120)=13650

13650-9500=4150

apply formula

(2x12x4150)/((13650(60+1))=0.1196

0.1196x100=11.96% 0r 12%

Drupady [299]3 years ago
6 0

Answer:

17.2%

Step-by-step explanation:

given that:

y = 12 months

m = $9,500

n = 60 (because five years is 60 months)

c = (n * $227.50) - m

  = (60 * $227.50) - $9,500

c = 4,150

and now, to substitute the following to the equation:

\frac{2(12)(4,150)}{9,500(61)} *100 = 17.2%

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cylinder shaped can needs to be constructed to hold 200 cubic centimeters of soup. The material for the sides of the can costs 0
Dafna11 [192]

Answer:

Radius=2.09 cm

Height,h=14.57 cm

Step-by-step explanation:

We are given that

Volume of cylinderical shaped can=200 cubic cm.

Cost of sides of can=0.02 cents per square cm

Cost of top and bottom of the can =0.07 cents per square cm

Curved surface area of cylinder=2\pi rh

Area of circular base=Area of circular top=\pi r^2

Total cost,C(r)=0.02\times 2\pi rh+2\pi r^2\times 0.07

Volume of cylinder,V=\pi r^2 h

200=\pi r^2 h

h=\frac{200}{\pi r^2}

Substitute the value of h

C(r)=0.02\times 2\pi r\times \frac{200}{\pi r^2}+2\pi r^2\times 0.07

C(r)=\frac{8}{r}+0.14\pi r^2

Differentiate w.r.t r

C'(r)=-\frac{8}{r^2}+0.28\pi r

C'(r)=0

-\frac{8}{r^2}+0.28\pi r=0

0.28\pi r=\frac{8}{r^2}

r^3=\frac{8}{0.28\pi}=9.095

r=(9.095)^{\frac{1}{3}}=2.09

Again, differentiate w.r.t r

C''(r)=\frac{16}{r^3}+0.28\pi

Substitute the value of r

C''(2.09)=\frac{16}{(2.09)^3}+0.28\pi=2.63>0

Therefore,the product cost is minimum at r=2.09

h=\frac{200}{\pi (2.09)^2}=14.57

Radius of can,r=2.09 cm

Height of cone,h=14.57 cm

4 0
3 years ago
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