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Readme [11.4K]
3 years ago
10

6th grade math, help me please:)

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
6 0

Answer:

8:3 is the ratio of kids to adults

32 kids, so there are 12 adults

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Find the distance between the pair of parallel lines, y = x-11 & y = x-7
kenny6666 [7]
k:\ y = x-11\ \ \ \Leftrightarrow\ \ \ x-y-11=0\\ and\\ l:\ y = x-7\ \ \ \Leftrightarrow\ \ \ x-y-7=0\\\\the\ distance:\\\\ d(k;l)= \frac{\big{|-11-(-7)|}}{\big{ \sqrt{1^2+1^2} }} =\frac{\big{|-11+7|}}{\big{ \sqrt{2} }} =\frac{\big{|-4|}}{\big{ \sqrt{2} }} =\frac{\big{4\cdot \sqrt{2} }}{\big{ \sqrt{2}\cdot \sqrt{2}  }} =\frac{\big{4 \sqrt{2} }}{\big{2 }} =2 \sqrt{2}
6 0
3 years ago
Read 2 more answers
A positive real number is 2 more than another. If the sum of the squares of the two numbers is 42, find the numbers.
Brilliant_brown [7]

Answer:

Step-by-step explanation:

From the first sentence x (the number) is 2 more than another number (y). So, x+2=y. The sum of the squares of the two numbers is 42, meaning that \\ (x+2)^{2}+y^{2}=42. First, we square root the ENTIRE equation to get rid of the square. If you do one thing to one side, you have to do it to the other. After this, we have x+2+y=\sqrt{42}. Now, we subtract 2 from the other side to isolate the variable. You can isolate either one but normally I go for x. Now we have x+y=\sqrt{42}+2. Now, we want to get y to the other side so we subtract it from the left side and the right side which gives us x=-y+\sqrt{42}+2. now we know what X is equal to. Now we plug in x for \\ (x+2)^{2}+y^{2}=42, which gives us          (-y+\sqrt42}+2+2)^{2}+y^{2}=42. Now we only have one variable which is what we want. Next, we square root the entire thing to get rid of the squares, which gives us -y+\sqrt{42}+4+y=\sqrt{42}. I got lost in my work. I must have done something wrong I cant find out. If anyone wants to pick up where I left off go ahead but there's a timer and I have one minute left. I cant finish the problem in a minute. I'm sorry and hopefully I lead you somewhere.

6 0
2 years ago
What is the simplest term for these fractions?
irinina [24]
3/4 

1/3

3/4

1/3 

7/12

5/6 

9/10 

2/3

2/5

1/4 

Hope this helps. 
Have a great day!
3 0
3 years ago
The area of a bulletin board is 55 ft2. The length is nine feet less than four times the width. Find the length and the width, i
galben [10]

Answer:

The length and width are 11ft and 5ft respectively

Step-by-step explanation:

let the

length = L

Width = W

Area = LW = 55

The length is nine feet less than four times the width

L = 4W - 9

W (4W - 9) = 55

4W^2 - 9W -55 = 0

4W^2 - 20W + 11W - 55 = 0

4W(W - 5) + 11(W - 5) = 0

(W - 5)(4W + 11) = 0

W - 5 = 0 , 4W + 11=0

W = 5 or  - 11/4

since the width cannot be negative, W = 5

LW = 55

L = 55/5

L = 11

The length and width are 11ft and 5ft respectively.

7 0
3 years ago
Please helpppppppppppppppppppppppppp<br><br><br> show your work<br><br><br> -25 x 25
puteri [66]
-625
use long multiplication to evaluate .
8 0
2 years ago
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