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Vitek1552 [10]
3 years ago
13

Evaluate the function. f(x) = -2x2 + 8x – 10 Find f(-4)

Mathematics
2 answers:
Andre45 [30]3 years ago
4 0

Answer:

f(-4)=-2(-4)²+8(-4)-10=-2×16-32-10=-74

LekaFEV [45]3 years ago
3 0

Step-by-step explanation:

Given

f(x) = - 2x² + 8x - 10

f(-4) = - 2 * (-4)² + 8 * ( -4 ) - 10

= - 32 - 32 - 10

= - 74

Hope it will help :)

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a student found the slope of a line that passes through the points (1,14) and (3,4) to be 5. what mistake did she make?
mariarad [96]
x_{1}=1
x_{2}= 3
y_{1} =14
y_{2}=4
Slope= \frac{rise}{run} = \frac{ y_{2} - y_{1} }{ x_{2} - x_{1} } = \frac{4-14}{3-1} = \frac{-10}{2} =-5


answer: The student flipped the y values
3 0
3 years ago
HELLPPPP ANSWERRR AND EXPLAIN!!!!!​
bixtya [17]

Answer:

No

Step-by-step explanation:

This is because K and B don't share the same angle measurement. They both will be different numbers that must equal 180 degrees. With that K will be corresponding with J while B will be corresponding with D.

Hope this Helped

5 0
3 years ago
Read 2 more answers
Find tan(a) in the triangle<br><br> Any help will be appreciated thank you
Cerrena [4.2K]

Answer:

b 24/25

Step-by-step explanation:

SOHCAHTOA

tan is Opposite over Adjacent sides of the triangle from the perspective of angle A

so the opposite side was 24 and the adjacent side was 25

so the answer is 24/25 aka B

7 0
3 years ago
Which fraction does point A show?<br> A.3/7<br> B.3/4<br> C.8/5<br> D.7/4
IgorLugansk [536]

Answer:

d 7/4

Step-by-step explanation:

6 0
3 years ago
Solve the equation <img src="https://tex.z-dn.net/?f=%2835%20x%5E%7B4%7D%20y%2B14%20x%5E%7B5%7D%20y-2%20y%5E%7B3%7D-4x%20y%5E%7B
jeka94
\underbrace{35x^4y+14x^5y-2y^3-4xy^3}_M\,\mathrm dx+\underbrace{7x^5-6xy^2}_N\,\mathrm dy=0

M_y=35x^4+14x^5-6y^2-12xy^2
N_x=35x^4-6y^2

\dfrac{N_x-M_y}N=\dfrac{-14x^5+12xy^2}{7x^5-6xy^2}=-2

This suggests an integrating factor depending on x only is possible, and given by

\mu(x)=\exp\left(-\displaystyle\int\frac{N_x-M_y}N\,\mathrm dx\right)=e^{2x}

Distributing across the ODE, we end up with

\underbrace{(35x^4y+14x^5y-2y^3-4xy^3)e^{2x}}_{M^*}\,\mathrm dx+\underbrace{(7x^5-6xy^2)e^{2x}}_{N^*}\,\mathrm dy=0

The equation is now exact, with

{M^*}_y={N^*}_x=(35x^4+14x^5-6y^2-12xy^2)e^{2x}

Now we find the solution:

F_x=M^*
F=\displaystyle\int(35x^4+14x^5-2y^3-4xy^3)e^{2x}\,\mathrm dx
F=(7x^5y-2xy^3)e^{2x}+f(y)

F_y=N^*
(7x^5-6xy^2)e^{2x}+f'(y)=(7x^5-6xy^2)e^{2x}
f'(y)=0
\implies f(y)=C

The general solution is then

F(x,y)=(7x^5y-2xy^3)e^{2x}=C
7 0
4 years ago
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