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g100num [7]
3 years ago
13

What are the possible solutions to 33⋅3333⋅33, if 11⋅11=411⋅11=4 and 22⋅22=1622⋅22=16?

Mathematics
1 answer:
SOVA2 [1]3 years ago
3 0

Since 11*11 = 4, therefore in this case 11 = 2. Since 22*22 = 16, therefore in this case 22 = 4. So we can see that the common ratio is 2. Based from this, we can say that 33 = 6.

So that:

33*33 = 36

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