1/4a-17=-15
1/4a=-15+17
1/4a=2
(1/4*4)a=(2*4)
a=8
Answer:
(a) 0.119
(b) 0.1699
Solution:
As per the question:
Mean of the emission,
million ponds/day
Standard deviation,
million ponds/day
Now,
(a) The probability for the water pollution to be at least 15 million pounds/day:


= 1 - P(Z < 1.178)
Using the Z score table:
= 1 - 0.881 = 0.119
The required probability is 0.119
(b) The probability when the water pollution is in between 6.2 and 9.3 million pounds/day:



P(Z < - 0.86) - P(Z < - 1.96)
Now, using teh Z score table:
0.1949 - 0.025 = 0.1699
Thank you for posting
your question here at brainly. Feel free to ask more questions.
f′(x)=2∗(8x(2−1))+1∗11x(1−1)
which is
f′(x)=16x+11
then let
x = 7 gives us
f′(7)=123
<span>
<span>Hope my answer would be a great help for you. </span> </span>
<span> </span>
We are given D (7, -3) and D'(2, 5).
SAppy the transformation
D'(x,y) → D(x-5, y+8).
Then
x=7 → x=7-5 = 2
y=-3 → y=-3+8 = 5
Answer: D (x-5, y+8) → D'
Answer:
Step-by-step explanation:
y= -5x/2+1