Answer:
6
Step-by-step explanation:
Answer:
Mary is 8 and that Zane and Chase are both 4 years old.
Step-by-step explanation:
For this equation, we will say Mary = M, Zane = Z, and Chase = C.
We will now convert the word problem into equations.

Now I will solve the equations by putting C into the equation.

So we can see that Mary is 8 and that Zane and Chase are both 4 years old.
The correct answer is: [A]: " 2x³ + 7x² + 12x − 8 " .
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Explanation:
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Given:
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" (x² + 4x + 8) (2x − 1) " ; Find the product:
↔ " (2x − 1) (x² + 4x + 8) " ;
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Note: " (a + b) (c + d + e) = ab + ad + ae + bc + bd + ae " .
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→ " (2x − 1) (x² + 4x + 8) =
(2x * x²) + (2x * 4x) + (2x *8) + (-1 * x²) + (-1 * 4x) + (-1 * 8) ;
= 2x³ + 8x² + 16x + (-1x²) + (-4x) + (-8) ;
= 2x³ + 8x² + 16x − x² − 4x − 8) ;
→ Combine the "like terms" :
+ 8x² − x² = + 7x² ;
+ 16x − 4x = + 12x ;
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And rewrite the expression:
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→ " 2x³ + 7x² + 12x − 8 " ;
→ which is: Answer choice: [A]: " 2x³ + 7x² + 12x − 8 " .
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Kyle purchased a 20 lb. pumpkin for $5.95.
Cost per lb of pumpkin for Kyle = 5.95/ 12 = $0.496.
Elizabeth purchased a 15 lb. pumpkin for $5.00.
Cost per lb of pumpkin for Elizabeth = 5.00/15 = $0.333.
Elijah purchased an 8 oz. pumpkin for $ 0.16.
16 oz = 1 lb
8 oz = 0.5 lb.
Cost per lb of pumpkin for Elijah = 0.16/ 0.5 = $ 0.32.
<h3>Cost per lb of pumpkin for Elijah is $ 0.32 is the lowest price per lb of pumpkin .</h3><h3>Cost per lb of pumpkin for Kyle is $ $0.496 is the highest price per lb of pumpkin .</h3><h3>Therefore, Elijah got the best deal and Kyle got the worst deal.</h3>
The initial investment = $250
<span>annual simple interest rate of 3% = 0.03
</span>
Let the number of years = n
the annual increase = 0.03 * 250
At the beginning of year 1 ⇒ n = 1 ⇒⇒⇒ A(1) = 250 + 0 * 250 * 0.03 = 250
At the beginning of year 2 ⇒ n = 2 ⇒⇒⇒ A(2) = 250 + 1 * 250 * 0.03
At the beginning of year 3 ⇒ n = 3 ⇒⇒⇒ A(2) = 250 + 2 * 250 * 0.03
and so on .......
∴ <span>The formula that can be used to find the account’s balance at the beginning of year n is:
</span>
A(n) = 250 + (n-1)(0.03 • 250)
<span>At the beginning of year 14 ⇒ n = 14 ⇒ substitute with n at A(n)</span>
∴ A(14) = 250 + (14-1)(0.03*250) = 347.5
So, the correct option is <span>D.A(n) = 250 + (n – 1)(0.03 • 250); $347.50
</span>