If a^2 + b^2 = c^2 then it is a right triangle.
22^2 + 26^2 ?=? 34^2
484 + 676 ?=? 1156
1160 ?=? 1156
This is NOT TRUE so it is not a right triangle.
Answer:
0
Step-by-step explanation:
Given :
Mean = 40 ; Standard deviation = 2
P(x < 28)
Obtain the Zscore :
Z = (x - mean) / standard deviation
P(Z < (28 - 40) / 2))
Z = (28 - 40) / 2
Z = - 12 / 2
Z = - 6
P(Z < - 6) = 0.000000
(8x 2 −15x)−(x 2 −27x)=ax 2 +bxleft parenthesis, 8, x, squared, minus, 15, x, right parenthesis, minus, left parenthesis, x, squ
quester [9]
Answer:
<h2>5</h2>
Step-by-step explanation:
Given the expression (8x² −15x)−(x² −27x) = ax² +bx, we are to determine the value of b-a. Before we determine the vwlue of b-a, we need to first calculate for the value of a and b from the given expression.
On expanding the left hand side of the expression we have;
= (8x² −15x)−(x² −27x)
Open the paranthesis
= 8x² −15x−x²+27x
collect the like terms
= 8x²−x²+27x −15x
= 7x²+12x
Comparing the resulting expression with ax²+bx
7x²+12x = ax²+bx
7x² = ax²
a = 7
Also;
12x = bx
b =12
The value of b - a = 12 - 7
b -a = 5
Hence the value of b-a is equivalent to 5
Some of the many possible answers can be..
3.3
2.2
0.5
I dont think the answer is 129 unless you typed the problem in wrong. Order of operations say to do everything inside the perenthesis first so you would do the 3*2 which is 6 then divide the 12 by 6 and you get 2. so your new equation is 8^2+9(2)-7. Next distribute the 9 to the 2 that is inside the perenthesis. Square root the 8 also. Now it is 49+18-7. The answer would be 60 ...?
