Similar figures are two different figures of different sizes, but have the same shape
Answer:
![Pr = 0.7282](https://tex.z-dn.net/?f=Pr%20%3D%200.7282)
Step-by-step explanation:
Given
--- sample size
-- defective
--- selected
Required
The probability that the batch will be accepted
When the first is selected, the probability that it is okay is:
![Pr(1) = \frac{2100-160}{2100} = \frac{1940}{2100}](https://tex.z-dn.net/?f=Pr%281%29%20%3D%20%5Cfrac%7B2100-160%7D%7B2100%7D%20%3D%20%5Cfrac%7B1940%7D%7B2100%7D)
<em>The subtraction is done to get the number of items that are not defective</em>
Now, there are 2099 left
For the second selection, the probability is:
![Pr(2) =\frac{2099-160}{2099} = \frac{1939}{2099}](https://tex.z-dn.net/?f=Pr%282%29%20%3D%5Cfrac%7B2099-160%7D%7B2099%7D%20%3D%20%5Cfrac%7B1939%7D%7B2099%7D)
Now, there are 2098 left
For the third selection, the probability is:
![Pr(3) =\frac{2098-160}{2098} = \frac{1938}{2098}](https://tex.z-dn.net/?f=Pr%283%29%20%3D%5Cfrac%7B2098-160%7D%7B2098%7D%20%3D%20%5Cfrac%7B1938%7D%7B2098%7D)
Now, there are 2097 left
For the fourth selection, the probability is:
![Pr(4) =\frac{2097-160}{2097} = \frac{1937}{2097}](https://tex.z-dn.net/?f=Pr%284%29%20%3D%5Cfrac%7B2097-160%7D%7B2097%7D%20%3D%20%5Cfrac%7B1937%7D%7B2097%7D)
So, the probability that the batch will be selected is:
![Pr = Pr(1) * Pr(2) * Pr(3) * Pr(4)](https://tex.z-dn.net/?f=Pr%20%3D%20Pr%281%29%20%2A%20Pr%282%29%20%2A%20Pr%283%29%20%2A%20Pr%284%29)
![Pr = \frac{1940}{2100} * \frac{1939}{2099} * \frac{1938}{2098} * \frac{1937}{2097}](https://tex.z-dn.net/?f=Pr%20%3D%20%5Cfrac%7B1940%7D%7B2100%7D%20%2A%20%5Cfrac%7B1939%7D%7B2099%7D%20%2A%20%5Cfrac%7B1938%7D%7B2098%7D%20%2A%20%5Cfrac%7B1937%7D%7B2097%7D)
![Pr = 0.7282](https://tex.z-dn.net/?f=Pr%20%3D%200.7282)
Answer:
The average rate of change between two input values is the total change of the function values (output values) divided by the change in the input values
What Do you need help with if you added a picture we cant see it