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11111nata11111 [884]
3 years ago
11

The lateral area of a regular pyramid with an octagonal base is 109.9 cm2. If the slant height is 6.7 cm, find the length of one

side of the base. Round to the nearest tenth.
A 2.1 m
B 16.4 m
C 32.8 m
D 4.1 m

Mathematics
1 answer:
irga5000 [103]3 years ago
3 0

Given pyramid with octagonal base. Image of the pyramid attached below:

We know the formula of Lateral Area of pyramid = \frac{1}{2} pl

where p represent the perimeter of the octagonal base

and l represent the slant height of the pyramid.

109.9 = \frac{1}{2}*p*6.7

Solve for p

p = 32.81 cm

Perimeter of octagonal base (all sides are same) = 8*s

where s represent the side of octagon

8s = 32.81

Solve for s

s = 4.1 cm

Side of the octagon = 4.1cm (option D)

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<span>The measure of angle SUT is equal to 90 degrees
</span>
Explanation:
The Pythagorean theorem states that:
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In other words:
(hypotenuse)² = (first side)² + (second side)²

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This means that the given triangle UST is a right-angled triangle and that side "u" is its hypotenuse.

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Based on the above:
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