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joja [24]
3 years ago
13

1 4/5 x 5/12 Please help!

Mathematics
2 answers:
emmainna [20.7K]3 years ago
6 0
All you have to do is to change a mixed number into a fraction. 1 x 5 = 5 + 4 = 9/5. Now 9/5 x 5/12 = 45/60
balandron [24]3 years ago
5 0
Is it 1-4/5 x 5/12 or 4/5 x 12 
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Something x something x something =70
nadya68 [22]
Here is what the answer to your question is:
7x10x1=70
5 0
3 years ago
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John runs a computer software store. Yesterday he counted 123 people who walked by the store, 56 of whom came into the store. Of
vaieri [72.5K]

Answer:

a) There is a 45.53% probability that a person who walks by the store will enter the store.

b) There is a 41.07% probability that a person who walks into the store will buy something.

c) There is a 18.70% probability that a person who walks by the store will come in and buy something.

d) There is a 58.93% probability that a person who comes into the store will buy nothing.

Step-by-step explanation:

This a probability problem.

The probability formula is given by:

P = \frac{D}{T}

In which P is the probability, D is the number of desired outcomes and T is the number of total outcomes.

The problem states that:

123 people walked by the store.

56 people came into the store.

23 bought something in the store.

(a) Estimate the probability that a person who walks by the store will enter the store.

123 people walked by the store and 56 entered the store, so T = 123, D = 56.

So

P = \frac{D}{T} = \frac{56}{123} = 0.4553

There is a 45.53% probability that a person who walks by the store will enter the store.

(b) Estimate the probability that a person who walks into the store will buy something.

56 people came into the store and 23 bought something, so T = 56, D = 23.

So

P = \frac{D}{T} = \frac{23}{56} = 0.4107

There is a 41.07% probability that a person who walks into the store will buy something.

(c) Estimate the probability that a person who walks by the store will come in and buy something.

123 people walked by the store and 23 came in and bought something, so T = 123, D = 23.

So

P = \frac{D}{T} = \frac{23}{123} = 0.1870

There is a 18.70% probability that a person who walks by the store will come in and buy something.

(d) Estimate the probability that a person who comes into the store will buy nothing.

Of the 56 people whom came into the store, 23 bought something. This means that 56-23 = 33 of them did not buy anything. So:

D = 33, T = 56

P = \frac{D}{T} = \frac{33}{56} = 0.5893

There is a 58.93% probability that a person who comes into the store will buy nothing.

8 0
3 years ago
Look at the right triangle ABC:
prisoha [69]

Answer:

The first incorrect justification is in step 2.

Step-by-step explanation:

<u>Step 2</u>. BC2 = AC • DC  

2. BC ÷ DC = BC ÷ AC because triangle ABC is similar to triangle BDC

It's supposed to be AC ÷ BC not BC ÷ AC.

8 0
4 years ago
Patrick paid $12 for<br> 25 pounds of candy.<br> How much did each<br> pound of candy cost?
tiny-mole [99]
$12/25 pounds

12/25= $0.48

$0.48/pound is your answer
7 0
3 years ago
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9s - 5g = -4y, for s
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S = (5g -4y)/9

hope this helps
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4 years ago
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