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Stella [2.4K]
3 years ago
7

1 kilometer:3 meter on the map. The distance from the school to the park is 4 meters on the map how many actual kilometers is it

?
Mathematics
1 answer:
Neporo4naja [7]3 years ago
8 0

Answer:

4 km

Step-by-step explanation:

1000m:3m = 4000m:12m

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Given than line a is parallel to line b and that line c is parallel to line d, if m<13=(12x-22) & m<14=(9x-29), find m
Lesechka [4]
13+14=180°
12x-22+9x-29=180
21x-51=180
x=11

m<2=m<14
m<2=70°
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Please help with 16 and 17 those are hard
notka56 [123]
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4 years ago
Which equation describes a line with a slope of -8 and includes the point (-4, 7)?
timurjin [86]
Such an equation would be y + 8x = - 25 (standard form) OR y = -8x - 25 (y-intercept form)
 
Deriving The Answer:

By using the point-slope form of the equation of a line, by knowing the gradient of that line and a point on that line, the equation of this line can be derived.

Now, the point-slope form exists as y - y₁ = m ( x - x₁)

since slope = -8 and the point on the line = (-4 , 7)

Then m = - 8
          x₁ = - 4
          y₁ =  7
                              ⇒  y - 7 = -8 ( x - (-4))

                              ⇒ y - 7 = -8x - 32

                              ⇒ y + 8x = - 25
                   


3 0
3 years ago
I need the A B C, it’s due tonight plz help
Tems11 [23]

Answer:

a = -2, b = -5, c = 1

I hope this helps

8 0
3 years ago
Read 2 more answers
HELP ASAP ILL MARK U BRAINLIEST! PLS
Alex17521 [72]

Answer:

144 ft

Step-by-step explanation:

The object's maximum height is the same as the y-coordinate of the vertex.

To find that, first, finds the x- coordinate(t).You can find it by: first identifying a, b and c.

Multiply the b by negative 1 or simply change its sign and divide it by 2a.

Afterward, plug the answer in the equation to find y, your answer.(ax+bx²+c=-16t²+64t+80).

Therefore, a=-6, b= 64 and c=80-64/2(-16)=-64/-32=2-16(2)²+64(2)+80=144 ft

So the maximum height of the object, when launched 64ft/sec from a platform that is 80 ft high, is 144 ft

8 0
3 years ago
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