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IrinaVladis [17]
3 years ago
6

What is the surface area of a box that is 6 by 4 inches

Mathematics
2 answers:
san4es73 [151]3 years ago
6 0

Answer:

The surface area of a box that is 6 by 4 inches is 24in²

KatRina [158]3 years ago
3 0
24n over 2 sorry if wrong!
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What will be the sign of the operation between the two terms in the squared binomial?
Allushta [10]

Answer:

We can find the square by multiplying the binomial by itself. However terms Lastly, we see that the first sign of the trinomial is the same as the sign of the binomial. For the middle term of the trinomial, double the product of the two terms.

Step-by-step explanation:

4 0
3 years ago
what is the equation in slope intercept form of the line that passes through the point (-4,47) and (2,-16)
Vilka [71]

The slope-intercept form:

y=mx+b

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (-4, 47) and (2, -16). Substitute:

m=\dfrac{-16-47}{2-(-4)}=\dfrac{-63}{6}=-\dfrac{63:3}{6:3}=-\dfrac{21}{2}

Therefore we have:

y=-\dfrac{21}{2}x+b

Put the coordinates of the point (2, -16) to the equation:

-16=-\dfrac{21}{2}(2)+b\\\\-16=-21+b\qquad\text{add 21 from both sides}\\\\5=b\to b=5

Answer: \boxed{y=-\dfrac{21}{2}x+5}

6 0
3 years ago
How can these models be used to find the sum 1.8 + 1.56?
enyata [817]

Answer:

The sum of  1.8 and 1.56 is 3.36 according to the model

Sum of decimals

Given the expression  1.8 + 1.56

Using the partial sum method

1.8 + 1.56 = (1.0 + 0.8) + (1.0+0.56)

Regroup as whole and decimal number

1.8 + 1.56 = (1.0 + 1.0) + (0.8 +0.56)

1.8 + 1.56 = 2.0 + 1.36

1.8 + 1.56 = 3.36

Hence the sum of  1.8 and 1.56 is 3.36 according to the model

3 0
2 years ago
Write an expression that has three terms and simplifies to 4x-7.
nikklg [1K]
You get 3x + 4x, +4- -3,and +3 + 4
4 0
3 years ago
GIVEN: LJ || WK || AP, PL || AG.
galina1969 [7]

Answer:

∠1 ≅ ∠2 ⇒ proved down

Step-by-step explanation:

#12

In the given figure

∵ LJ // WK

∵ LP is a transversal

∵ ∠1 and ∠KWP are corresponding angles

∵ The corresponding angles are equal in measures

∴ m∠1 = m∠KWP

∴ ∠1 ≅ ∠KWP ⇒ (1)

∵ WK // AP

∵ WP is a transversal

∵ ∠KWP and ∠WPA are interior alternate angles

∵ The interior alternate angles are equal in measures

∴ m∠KWP = m∠WPA

∴ ∠KWP ≅ ∠WPA ⇒ (2)

→ From (1) and (2)

∵ ∠1 and ∠WPA are congruent to ∠KWP

∴ ∠1 and ∠WPA are congruent

∴ ∠1 ≅ ∠WPA ⇒ (3)

∵ WP // AG

∵ AP is a transversal

∵ ∠WPA and ∠2 are interior alternate angles

∵ The interior alternate angles are equal in measures

∴ m∠WPA = m∠2

∴ ∠WPA ≅ ∠2 ⇒ (4)

→ From (3) and (4)

∵ ∠1 and ∠2 are congruent to ∠WPA

∴ ∠1 and ∠2 are congruent

∴ ∠1 ≅ ∠2 ⇒ proved

8 0
3 years ago
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