The cafeteria manager took a poll of 150 students to find the most popular lunch.

zimovet [89]

The only equation that works with x=-6 is A

7 0

3 years ago

A medical researcher wondered if there is a significant difference between the mean birth weight of boy and girl babies. Random

Yuliya22 [10]

Answer:

b) independent samples t-test

$t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154$

$p_v =2*P(t_{8}>0.154) =0.881$

So with the p value obtained and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).

Step-by-step explanation:

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 = \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

Or equivalently:

Null hypothesis: $\mu_1 - \mu_2 = 0$

Alternative hypothesis: $\mu_1 -\mu_2\neq 0$

Our notation on this case :

$n_1 =5$ represent the sample size for group 1

$n_2 =5$ represent the sample size for group 2

We can calculate the mean and deviation for eaach group with the following formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X_1 =5.92$ represent the sample mean for the group 1

$\bar X_2 =5.74$ represent the sample mean for the group 2

$s_1=1.88$ represent the sample standard deviation for group 1

$s_2=1.81$ represent the sample standard deviation for group 2

If we see the alternative hypothesis we see that we are conducting a bilateral test and with independnet samples t test.

b) independent samples t-test

The statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{S^2_2}{n_2}}$

And now we can calculate the statistic:

$t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154$

The degrees of freedom are given by:

$df=5+5-2=8$

And now we can calculate the p value using the altenative hypothesis:

$p_v =2*P(t_{8}>0.154) =0.881$

So with the p value obtained and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).

7 0

4 years ago

HELP ME! <br>Please, I will give brainliest and extra points :) Thank you

Arte-miy333 [17]

Answer:

solution set of f(x) = g(x) is x∈{0,1}

Step-by-step explanation:

For all exponential functions b^x,

b^0 is always 1, and b^1 is always b.

f(x) = -3/4 x + 2

g(x) = (1/4)^x + 1

g(0) = 2, f(0) = 2

g(1) = 5/4, f(1) = 5/4

7 0

4 years ago

Sue has $74,210 in a savings account. The interest rate is 15% per year and is not compounded. How much will she have in 2 years

MrRa [10]

Answer:

$22,263

Step-by-step explanation:

15% of $74,210 is $11,131.50 so $11,131.50 X 2= $22,263

so after 2 years the total amount of money along with interest will be a total of = $96,473

8 0

3 years ago

PWEASE HELPPPPP

AveGali [126]

Answer:

For the length I think you meant 32, and if you did it is $14.40

If not and you meant length of 2 it is $0.90

Step-by-step explanation:

6 0

3 years ago

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