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Kipish [7]
3 years ago
12

Pleaseeeee helppppp will mark you as brainlist

Mathematics
1 answer:
Phoenix [80]3 years ago
6 0

Answer:

24.292488551

Step-by-step explanation:

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The weight of a product is normally distributed with a mean of four ounces and a variance of .25 "squared ounces." The company w
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Weight=2.835

Step-by-step explanation:

See the attached picture for explanation.

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Select the correct answer from the drop-down menu.
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control group

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2 years ago
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Calls to a customer service center last on average 2.8 minutes with a standard deviation of 1.4 minutes. An operator in the call
Natali5045456 [20]

Answer:

The expected total amount of time the operator will spend on the calls each day is of 210 minutes.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

n-values of normal variable:

Suppose we have n values from a normally distributed variable. The mean of the sum of all the instances is M = n\mu and the standard deviation is s = \sigma\sqrt{n}

Calls to a customer service center last on average 2.8 minutes.

This means that \mu = 2.8

75 calls each day.

This means that n = 75

What is the expected total amount of time in minutes the operator will spend on the calls each day

This is M, so:

M = n\mu = 75*2.8 = 210

The expected total amount of time the operator will spend on the calls each day is of 210 minutes.

6 0
3 years ago
What is the fifth square root of x^16
melamori03 [73]
The fifth square root as in a^(1/2)^(1/2)^(1/2)^(1/2)^(1/2)

Well that is equal to a^((1/2)^5) or a^(1/32)

Since a=x^16 in this case and the rule (b^a)^c=b^(a*c) we have:

(x^16)^(1/32)

x^(16/32)

x^(1/2) or if you prefer

√x


8 0
3 years ago
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