Answer:
The inverse for log₂(x) + 2 is - log₂x + 2.
Step-by-step explanation:
Given that
f(x) = log₂(x) + 2
Now to find the inverse of any function we put we replace x by 1/x.
f(x) = log₂(x) + 2
f(1/x) =g(x)= log₂(1/x) + 2
As we know that
log₂(a/b) = log₂a - log₂b
g(x) = log₂1 - log₂x + 2
We know that log₂1 = 0
g(x) = 0 - log₂x + 2
g(x) = - log₂x + 2
So the inverse for log₂(x) + 2 is - log₂x + 2.
Answer:
the top 2 and the left bottom corner
Step-by-step explanation:
the first one in the first row is a reflection
the second one in the first row is a rotation
the one on the left bottom corner just moved a unit
Answer:
Step-by-step explanation:
Setting it up as a fraction will help us see the simplification process a bit easier.
a/a = 1, so they cancel each other out, leaving us with simply
Step-by-step explanation:
i think the answer is 1/9
Answer: 1.83
Step-by-step explanation:
