Answer:
Step-by-step explanation:
The first one is actually 0 I think. The instantaneous ROC at x=1 should also be 0. The last one should be correct.
Basically, the ROC for the first one is 0 because the y value at the start and end of the interval is the same, so the change is the same. However, for the instantaneous ROC at x = 0, you look at the graph and realize that if you find the derivative at that point, it is 0.
Number of zids=x
number of zods=y
number of zid legs=5x
number of zod legs=7y
so
5x+7y=140
try to get it into slope intercept from so you can graph is (y=mx+b)
5x+7y=140
subtract 5x from both sides
7y=140-5x
divide both sides by 7
y=20-5/7x
y=-5/7x+20
plug in numbers for x and get numbers for y (you can only plug in multiples of 7 for x so that there are a whole number of zids and since you are counting, x and y must never be negative)
lets try 0 for x
y=-5/7(0)+20
y=20
so x=0 and y=20 is an answer (if you can have only one of that species)
lets try 7 for x
y=-5/7(7)+20
y=-5+20
y=15
so x=7 and y=15 is an answer
lets try 14 for x
y=-5/7(14)+20
y=-10+20
y=10
so x=14 and y=10 is another answer
lets try 21 for x
y=-5/7(21)+20
y=-15+20
y=5
so x=21 and y=5 is another answer
lets try 28 for x
y=-5/7(28)-20
y=-20+20
y=0
so x=28 and y=0 is an answer (if there can be only one of a species)
if we go further, then y will be negative so the answers are
(x,y)
(0,20)
(7,15)
(14,10)
(21,5)
(28,0)
if it is allowed that only one species exists then there are 5 possible answers
if both must exist simultaneously, then there are only 3 answers
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Answer:
A) If it is the weekend, then it is Saturday.
B) False
C) If it is the first day of the weekend, then it is Saturday. If it is Saturday, then it is the first day of the weekend.
~theLocoCoco
4m+2 (m-5)=26
4m+2m-10=26
6m-10=26
6m=36
M=6
Yes, the line passes the vertical line test (no x-values are repeated)
