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3 years ago

Can anyone name 5 fish of the sea. Be specific.

Biology

1 answer:

jeka943 years ago

3 0

Tiger Shark
Clown fish
Northern Puffer
Spanish Mackerel
Swordfish

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Which of the following describes an allele whose characteristic phenotype is masked by the presence of a second, different allel

brilliants [131]

The allele that can mask the presence of another allele is called dominant. The allele that is masked is recessive and if both alleles can be detected in the phenotype, then they are codominant. If they produce an intermediate phenotype like pink instead of red or white, then they have a relationship of incomplete dominance.

6 0

3 years ago

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You are enjoying a spring day but expect a storm to arrive soon. As the storm arrives and the rain begins to fall, you notice th

anastassius [24]

Answer:

c. Cold front

Explanation:

Cold fronts are bodies of air with cooler temperatures than the surrounding air. The general effect cold fronts have is that they cause a drastic change in the weather. This is because when they interact with the warmer air, they produce precipitation.

The storm most likely, came with an advancing mass of cold air, which caused the dramatic drop in temperature that was experienced. This is what is known as a cold front.

5 0

3 years ago

25 POINTS

Evgesh-ka [11]

It would be amino acids

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8 0

3 years ago

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Which question could be tested in a scientific manner?

german

Answer:

A. What causes some people to be color-blind?

Explanation:

This is something that could be tested with different variables including DNA, or past family medical history.

3 0

3 years ago

In a plant, leaf color and leaf shape are controlled by two linked genes Leaves of the wild-type plant are red. A recessive muta

Brrunno [24]

Solution :

Red is dominant over the white leaves and pointed is dominant over smooth.

Red = R , white = r

Pointed = P , smooth = p

Red, pointed x white,smooth ------ Parents

RRPP rrpp

RP rp ----------------- Gametes

RrPp -------- $F_1$

(red, pointed)

When this $F_1$ is test crossed,

RrPp x rrpp ---- $F_1$ test cross

Gametes → rp

RP ---------- RrPp - red, pointed - 36 parental type

Rp ---------- Rprp - red, smooth - 14 re- combination

rP ----------- rrPp - white pointed - 10 re- combination

rp ----------- rrpp - white, smooth - 40 - parental type

Total = 100

As this ratio is deviating from 1:1:1:1, it indicated the two genes are linked.

Linkage strength = percentage of crossing over = map distance between the genes.

Percentage crossing = recombination frequency = percentage of recombination.

Recombination frequency $=\frac{\text{total no. of recombination}}{\text{total no. of progeny}}\times 100$

$=\frac{14+10}{100} \times 100$

= 24 %

= 24 map units

4 0

3 years ago