Answer:
Let O be the common center of two concentric circles and let AB be a chord of larger circle touching the smaller circle at P join OP
Since OP is the radius of the smaller circle to any chrod of the circle bisects the chord.
∴ AP=BP
In right ΔAPO we have
OA
2
=AP
2
+OP
2
⇒25−9=AP
2
⇒AP
2
=16⇒AP=4
Now AB=2,AP=2×4=8[∵AP=PB]
hence the length of the chord of the larger circle which touches the smaller circle is 8cm.
Step-by-step explanation:
Answer:
m = 24
Step-by-step explanation:
m + 7° + 2m + 11° = 90°
3m + 18° = 90°
3m = 90°- 18°
3m = 72
(divide both sides by 3)
therefore : m = 24
Step-by-step explanation:
of a right triangle if the longer leg is 11 feet more than the shorter leg and the hypotenuse is 11 feet less than twice the shorter leg.
Answer:
The middle one unless your solving for it its the yellow one
Step-by-step explanation:
Answer:
B. NB and DH
B. converse of corresponding angles theorem
Step-by-step explanation:
The transversal in this geometry is line BH. The angles marked 36° are on the same side of the transversal, and on the same sides of the intersecting lines NB and DH. That makes these congruent angles "corresponding" angles.
Segments NB and DH are parallel by the converse of the corresponding angles postulate.
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<em>Additional comment</em>
The <em>corresponding angles postulate</em> tells you corresponding angles are congruent where a transversal crosses parallel lines. Its converse tells you the lines are parallel if the corresponding angles are congruent.
<em>Corresponding</em> angles lie in the same direction from the vertex where the transversal meets one of the parallel lines. Here, the angles are "northwest" of the vertex.
