Answer:
You must survey 784 air passengers.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error is:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
Assume that nothing is known about the percentage of passengers who prefer aisle seats.
This means that
, which is when the largest sample size will be needed.
Within 3.5 percentage points of the true population percentage.
We have to find n for which M = 0.035. So






You must survey 784 air passengers.
2 71
3 86
4 101
6 131
.................
To round to the nearest tenth place you are going to round the last two digits of that, you should get 519.7
Density=mass/volume
given mass=120g and volume=200cm3
density=

or abot 0.6
the density is
Answer:
32.25
Step-by-step explanation: