C because you need to use the formula and then calculate
The answer is: "
11 " .
____________________________________________________ → "
x = 11 " .
____________________________________________________Explanation:____________________________________________________Set up the ratio/ proportion as a fraction:
6 cm / 48 cm = 5 cm / (3x + 7) ;
→ The "cm" units cancel out; since: "cm/cm = 1 " ;
→ The "6/48" = "(6 ÷ 6) / (48 ÷ 6) = " 1/8 " ;
→ Rewrite as:

;
Now, we can "cross-multiply" :
__________________________________________________<u>Note</u>: 
;

;
{b

; d

} .
__________________________________________________ As such:
1 * (3x + 7) = 8 * 5 ;
→ 3x + 7 = 40 ;
Subtract "
7" from each side of the equation:
→ 3x + 7 − 7 = 40 <span>− 7 ;
</span>
to get:
→ 3x = 33 ;
Now, divide each side of the equation by "
3" ;
to isolate "x" on one side of the equation; & to solve for "x" ;
→ 3x / 3 = 33 / 3 ;
to get:
____________________________________________________ → "
x = 11 " .
____________________________________________________ →
The answer is: "
11 " .
____________________________________________________
Answer:
115
Step-by-step explanation:
20% is one fifth. If Mary has one fifth fewer than Susan, then she has 4 fifths of what Susan has. So 92 is 4 fifths of some number.
To find out what one fifth is, you can divide 92 by 4 because it is four fifths.
92/4 = 23
So one fifth of the number of blouses Susan has is 23. Now you can multiply 23 by 5 to get the total number of blouses Susan has.
23 * 5 = 115
Answer:
167.49
Step-by-step explanation:
124.99 plus 42.50
hope this helps
Answer:
First term a = 3
Sum of first 20 term = 440
Step-by-step explanation:
Given:
8th term of AP = 17
12th term of AP = 25
Find:
First term a
Sum of first 20 term
Computation:
8th term of AP = 17
a + 7d = 17 ....... EQ1
12th term of AP = 25
a + 11d = 25 ...... EQ2
From EQ1 and EQ2
4d = 8
d = 2
a + 7d = 17
a + 7(2) = 17
First term a = 3
Sum of first 20 term
Sn = [n/2][2a + (n-1)d]
S20 = [20/2][(2)(3) + (20-1)2]
S20 = [10][(6) + 38]
S20 = [10][44]
S20 = 440
Sum of first 20 term = 440