Question

Shiloh has to earn at least $200 to meet her fundraising goal. She has only 100 cakes that she plans to sell at 5 dollars each. Which inequality shows the number of cakes, x, Shiloh can sell to meet her goal?

Answer 1

Answer:

$40 \leq x \leq 100$

Step-by-step explanation:

Cost of 1 cake = $5

Let x be the no. of cakes

So, Cost of x cakes = 5x

Since we are given that Shiloh has to earn at least $200

So, $5x\geq 200$

$x\geq 40$

So, the no. of the cakes should be sold more than or equal to 40

We are also given that She has only 100 cakes

So, the maximum number of cakes she can sold is 100 i.e.$x\leq 100$

So, Inequality becomes : $40 \leq x \leq 100$

Hence inequality shows the number of cakes, x, Shiloh can sell to meet her goal is $40 \leq x \leq 100$

Answer 2

She will only have to sell 40 cakes to earn $200