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IRISSAK [1]
3 years ago
9

The scale factor of the scale drawing of a mirror to the actual mirror is represented by the ratio 1 : 8 . If the dimensions of

the scale drawing are 3 inches wide by 8.5 inches long, what is the actual area of the mirror?
Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
8 0

Answer: 204 square inches

Step-by-step explanation: I’m not really sure, but if you follow through with the normal area identifying method; Length x Width, you should come up with 25.5. After doing this, you could multiply your product by 8 because your actual mirror size is 8 times greater. You will come up with 204 square inches, which would be your final solution. (Once again, I am not sure, just doing how I’ve been understanding from studies).

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Let E be the angle of elevation from the car to the end of the ramp. We now know that the hypotenuse of our triangle measures 445 feet, and the opposite side measures 80 feet, so we need a trig function that relates our angle of elevation with the hypotenuse and the opposite side. That function is sine:
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