What is an equation of the line that passes through the point (-6, -1) and is perpendicular to the line 6x-y= 7?
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Answer:
28 degrees
Step-by-step explanation:
If two parallel lines are cut by a transversal, then the pairs of corresponding angles are congruent.The corresponding angles are the ones at the same location at each intersection.
In the figure ABD and EDF are corresponding angles. So they are equal
So equation the angle ABD and EDF , we get
(3x+4) = (7x-20)
Group the like terms,
3x-7x = -20-4
-4x = -24
x = 6
Thus BCD will be,
(6x - 8)
=>(6(6)-8)
=>(36-8)
=> 28 degrees