Answer:
To check all the events (6), we label the chips. Suppose one chip with 1 is labeled R1 and the other B1 (as if they were red and blue). Now, lets take all combinations; for the first chip, we have 4 choices and for the 2nd chip we have 3 remaining choices. Thus there are 12 combinations. Since we dont care about the order, there are only 6 combinations since for example R1, 3 is the same as 3, R1 for us.
The combinations are: (R1, B1), (R1, 3), (R1, 5), (B1, 3), (B1, 5), (3,5)
We have that in 1 out of the 6 events, Miguel wins 2$ and in five out of the 6 events, he loses one. The expected value of this bet is: 1/6*2+5/6*(-1)=-3/6=-0.5$. In general, the expected value of the bet is the sum of taking the probabilities of the outcome multiplied by the outcome; here, there is a 1/6 probability of getting the same 2 chips and so on. On average, Miguel loses half a dollar every time he plays.
please mark me brainliest :)
<span>Solution above is incorrect, simplify as follows:
-(7c-18)-2c > 0
-7c+18-2c > 0
-9c > -18
c < 2</span>
Step-by-step explanation:
If all of these are supposed to be a length in a different dimension (a 6d object), then just multiply all of them like you would do in 3d.
14*8*10*10*10*8 = 896000 cm^6
If this is supposed to be a 3d object and all the sides with equal length are just supposed to be going in the same direction, multiply one of each of the lengths.
14*8*10 = 1120 cm^3
That isn't a question... we can't help you if we don't know what you're asking
Answer:
Three hundred
Step-by-step explanation:
Because the whole number is sixteen thousand THREE HUNDRED forty four
