Charlie made hamburgers

Which equation represents the relationship in the graph? giving brainliest!!!

Xelga [282]

A，the intercept is equal to 70

6 0

2 years ago

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A square room has a perimeter of 40 feet. What is the area of the room?

Trava [24]

Answer:

100 ft²

Step-by-step explanation:

There are 4 congruent sides in a square

Perimeter = 4x

40 = 4x

x = 10

Area = base x height or length x width

Since all sides are the same, 10 is base and height

10x10 = 100

units = ft²

Answer = 100 ft²

If my answer is incorrect, pls correct me!

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-Chetan K

4 0

2 years ago

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What is 5/6 plus 7/8?

irina [24]

Answer:

1 17/24

Step-by-step explanation:

8 0

3 years ago

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Location is known to affect the number, of a particular item, sold by an auto parts facility. Two different locations, A and B,

Mama L [17]

We have two samples, A and B, so we need to construct a 2 Samp T Int using this formula:

$\displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} }$

In order to use t*, we need to check conditions for using a t-distribution first.

Random for both samples -- NOT STATED in the problem ∴ proceed with caution!
Independence for both samples: 130 < all items sold at Location A; 180 < all items sold at Location B -- we can reasonably assume this is true
Normality: CLT is not met; n < 30 for both locations A and B ∴ proceed with caution!

Since 2/3 conditions aren't met, we can still proceed with the problem but keep in mind that the results will not be as accurate until more data is collected or more information is given in the problem.

Solve for t*:

We need the tail area first.

$\displaystyle \frac{1-.9}{2}= .05$

Next we need the degree of freedom.

The degree of freedom can be found by subtracting the degree of freedom for A and B.

The general formula is df = n - 1.

df for A: 13 - 1 = 12
df for B: 18 - 1 = 17
df for A - B: |12 - 17| = 5

Use a calculator or a t-table to find the corresponding t-score for df = 5 and tail area = .05.

t* = -2.015

Now we can use the formula at the very top to construct a confidence interval for two sample means.

$\overline {x}_A=39$
$s_A=8$
$n_A=13$
$\overline {x}_B = 55$
$s_B=2$
$n_B=18$
$t^{*}=-2.015$

Substitute the variables into the formula: $\displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} }$ .

$39-55 \ \pm \ -2.015 \big{(}\sqrt{\frac{(8)^2}{13} +\frac{(2)^2}{18} } } \ \big{)}$

Simplify this expression.

$-16 \ \pm \ -2.015 (\sqrt{5.1453} \ )$
$-16 \ \pm \ 3.73139$

Adding and subtracting 3.73139 to and from -16 gives us a confidence interval of:

$(-20.5707,-11.4293)$

If we want to interpret the confidence interval of (-20.5707, -11.4293), we can say...

We are 90% confident that the interval from -20.5707 to -11.4293 holds the true mean of items sold at locations A and B.

5 0

1 year ago

Find the range, mean, median, and mode of the following data set.

attashe74 [19]

Answer:

The answer to your question would be D.

D. Range: 20

Mean: 10

Median: 9

Mode: none

Step-by-step explanation:

1, 2, 3, 8, 9, 12, 14, 20, 21

Range: 21 - 1 = 20

Mean: 1 + 2 + 3 + 8 + 9 + 12 + 14 + 20 + 21 = 90/9 = 10

Median: 9

Mode: there are no mode in the following given data set.

8 0

3 years ago