All categories

2 years ago

What are the solutions to the system of equations? y=2x^2−6x+3 y=2x+3

Mathematics

1 answer:

adoni [48]2 years ago

5 0

Answer:

Step-by-step explanation:

y=2x²-6x+3

y=2x+3

2x²-6x+3=2x+3

2x²-6x+3-2x-3=0

2x²-8x=0

2x(x-4)=0

x=0,4

y=0+3=3

and y=2(4)+3=11

so solutions are (0,3) and (4,11)

You might be interested in

How do you do fraction ,like 20 on top line then 30 on bottom ,I was bad art math sorry please explaine to my daughter so she ca

telo118 [61]

Alright, so since I don't have an example question, I will make one up.

there are 8 coins in total. there are 6 dimes. What is the fraction of dimes to coins.

you would put the amount of dimes on the top and the total on the bottom.

Answer: 6/8 which can be simplified to 3/4

Or another Example:

There are 12 pieces in the pizza. Billy took 4. what is the fraction of the slices left.

it would be 4-12= 8

Answer: 8/12 which can be simplified to 4/6 and then to 2/3

Hope that helped.

8 0

2 years ago

Read 2 more answers

What is the mean of 65,30,25

mixas84 [53]

You've got 3 values there.

Get the sum of 65, 30 and 25 and divide their sum by the number of values that exist, which in this case is 3.

$\frac { 65+30+25 }{ 3 } =\frac { 120 }{ 3 } =40$

Answer:

40

5 0

3 years ago

Read 2 more answers

HELP NEEDED !!!!

Fofino [41]

The answer is Letter D - 84%

68% of the data is within +/- 1 SD from the mean = 59 to 7195% of the data is within +/- 2 SDs from the mean = 53 to 7799.7% of the data is within +/- 3 SDs from the mean = 47 to 83

The whole 68% (59 - 71) scored below 71. Since the data are evenly distributed, we'll get the 32% (100 - 68) outside the range of 68% and divide it by 2 and add the quotient to the original 68% so that we'll get the total data below 71.
100 - 68 = 32
32 / 2 = 16
16 + 68 = 84

7 0

3 years ago

How would you solve 7 - 3y = 22

nydimaria [60]

7-3y=22 -7 -7 -3y=15 Divide by -3. y=-5

7 0

3 years ago

Read 2 more answers

Given that x-1 and x+2 are factors of f(x)=x³+px+q where p and q are integers, find p and q. Hence, find the remainder when x³+p

alexandr1967 [171]

Answer:

p = -3
q = 2
remainder = 4

Step-by-step explanation:

We want to find the constants 'a', 'p', and 'q' such that ...

(x -a)(x -1)(x +2) ≡ x³ +px +q

(x -a)(x² +x -2) ≡ x³ +px +q

x³ +x² -2x -ax² -ax +2a ≡ x³ +px +q

This gives rise to three equations:

1 -a = 0 . . . . coefficient of x²

-2 -a = p . . . coefficient of x

2a = q . . . . . constant

The first of these tells us a=1. Then, p=-3 and q=2.

The values of p and q are -3 and 2, respectively.

The remainder from division by (x+1) is the value of the cubic for x=-1. That value is ...

(-1)³ -3(-1) +2 = -1 +3 +2 = 4

The remainder from division by (x+1) is 4.

7 0

2 years ago