Answer:
0.50 kg of the material would be left after 10 days.
0.25 kg of the material would be left after 20 days.
Step-by-step explanation:
We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after 10 days and 20 days, respectively.
We will use half life formula.
, where,
A = Amount left after t units of time,
a = Initial amount,
t = Time,
h = Half-life.




Therefore, amount of the material left after 10 days would be 0.5 kg.





Therefore, amount of the material left after 20 days would be 0.25 kg.
Here is the work hope this helps!
The formula to find the rate of change is y2-y1/x2-x1
6-(-4)/-3-(-1)
=10/-2
=-5
*115*
do the parentheses in the parentheses first, then the outer parentheses, then the stuff outside the parentheses.
PEMDAS
parentheses...exponents...multiplication/division...Addition/subtraction.
Answer:
B) 7.5 in3
Step-by-step explanation: