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Daniel [21]
3 years ago
10

What is an equation of the line that passes through the points (6, 0) and (-1, -7)?

Mathematics
1 answer:
Orlov [11]3 years ago
6 0

Answer:

y = x - 6

Step-by-step explanation:

We want to write a line in slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept.

First, we need to find the slope, which is just the change in the y-coordinates divided by the change in the x-coordinates:

slope = m = \frac{6-(-1)}{0-(-7)} =\frac{7}{7}=1

Our equation now looks like this: y = x + b

Now, to find the y-intercept, let's use one of the points provided and plug those values of x and y into the incomplete equation we have to solve for b:

0 = 6 + b  ⇒  b = -6

So, the equation is: y = x - 6.

Hope this helps!

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In the figure,ABC is a right-angled triangle.PQ=24cm,PR=45cm and T is a point on QR such that PT丄QR.Find PT.
snow_tiger [21]

RQ² = RP² + PQ²

RQ² = 45² + 24²

RQ² = 2025 + 576

RQ² = 2601

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PT = (24/51) × 45

PT = (8/17) × 45

PT = 360/17

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∠BDC and ∠AED are right angles, is  a piece of additional information is appropriate to prove △ CEA ~ △ CDB

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Image is attached below,
as shown in figure
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zhannawk [14.2K]

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subtracting 4x from both sides gives

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\begin{gathered} \text{FGI}=\text{HGI}+\text{FGH}=31+31 \\ FGI=62^o \end{gathered}

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BabaBlast [244]

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