∠BDC and ∠AED are right angles, is a piece of additional information is appropriate to prove △ CEA ~ △ CDB
Triangle AEC is shown. Line segment B, D is drawn near point C to form triangle BDC.
<h3> What are Similar triangles?</h3>
Similar triangles, are those triangles which have similar properties,i.e. angles and proportionality of sides.
Image is attached below,
as shown in figure
∡ACE = ∡BCD ( common angle )
∡AED = ∡BDC ( since AE and BD are perpendicular to same line EC and make right angles as E and C)
∡EAC =- ∡DBC ( corresponding angles because AE and BD are parallel lines)
Thus, △CEA ~ △CDB , because of the two perpendiculars AE and BD.
Learn more about similar triangles here:
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The sum of the interior angles is 360
The line GH bisects The triangle FGI meaning it divides it into two equal parts <em>(that is the definition if bisection); </em>therefore, the angles FGH and HGI are equal:

Now let us add 2 to both sides gives

subtracting 4x from both sides gives


Hence, x = 11.
The measure of FGH is

(B)
The measure of HGI is

(C)
The measure of FGI is the sum of HGI and FGH:

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Answer:
Find the slope of the original line and use the point-slope formula
y−y1=m(x−x1) to find the line parallel to y=2x−7. y=2x+12