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Leviafan [203]
3 years ago
13

describe how you can move shape 1 to exactly match shape 2 buy using one translation and one reflection

Mathematics
1 answer:
Artemon [7]3 years ago
3 0
Reflect the shape over the x axis, then translate it 8 units right and 3 units down.
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What causes a repeating decimal in the long division algorithm?
Nady [450]

Answer:

Step-by-step explanation:

In the division algorithm, if the remainder is zero, then the algorithm terminates, resulting in a terminating decimal. remainder repeats, the calculations that follow will also repeat in a cyclical pattern causing a repeating decimal.

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The quotient of a number and 3 is 9.
solong [7]
I need help my self lol
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The surface area of the pyramid with square base that measures 8 ft by 8 ft and slant height of 12 ft is 256 ft^2.
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A square garden has a side length of 11 meters. What is the area of the garden? What is the perimeter?
Talja [164]

Answer:

<em>Area</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>garden</em><em>=</em><em>1</em><em>2</em><em>1</em><em> </em><em>square</em><em> </em><em>meter</em>

<em>perimeter</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>garden</em><em>=</em><em>4</em><em>4</em><em> </em><em>meter</em>

Step-by-step explanation:

Area of a square=side*side

=11*11

=<u>1</u><u>2</u><u>1</u><em><u>s</u></em><em><u>q</u></em><em><u>u</u></em><em><u>a</u></em><em><u>r</u></em><em><u>e</u></em><em><u> </u></em><em><u>meter</u></em>

Perimeter of a square garden=side*4

=11*4

=44 m

6 0
3 years ago
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Find the derivative of f(x) = 2x^2 - 4x +3
ivolga24 [154]

Explanation

2x^2-4x+3

When taking derivatives of polynomials, we primarily make use of the power rule.

Power rule.

\begin{gathered} f(x)=x^n \\ \text{then} \\ f^{\prime}(x)=nx^{n-1} \end{gathered}

also, the derivate of a sum is the sum of the derivates

hence

\begin{gathered} g(x)=f(x)+h(x)+\ldots z(x) \\ g^{\prime}(x)=f^{\prime}(x)+h^{\prime}(x)+\ldots.z^{\prime}(x) \end{gathered}

Step 1

apply:

\begin{gathered} f(x)=2x^2-4x+3 \\ f^{\prime}(x)=2\cdot2x^{2-1}-4(1)x^{1-1}+ \\ f^{\prime}(x)=4x^{}-4(1)x^0+3^0 \\ f^{\prime}(x)=4x^{}-4(1)(1) \\ f^{\prime}(x)=4z-4 \end{gathered}

therefore, the answer is

8 0
1 year ago
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