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Leviafan [203]
3 years ago
13

describe how you can move shape 1 to exactly match shape 2 buy using one translation and one reflection

Mathematics
1 answer:
Artemon [7]3 years ago
3 0
Reflect the shape over the x axis, then translate it 8 units right and 3 units down.
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Simplify<br> 5m - 7 - 8m + 10
Bogdan [553]

Answer:

−3m + 3

Step-by-step explanation:

8 0
3 years ago
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What is the solution of the system? Use a graph.<br> y = –x + 2<br> y = 3x – 1
laila [671]
-x+2=3x-1
3=4x
3/4=x

Y=3(3/4)-1
Y=(9/4)-(4/4)
Y=5/4

7 0
2 years ago
The diagonal of square ABCD intersect at point E. If BE = 10 then which of the following represents the length of AB
Anestetic [448]

Answer :

c = 10 radical 2

Step-by-step explanation:

10^2 + 10^2 = c^2

100 + 100 = c^2

200 = c^2

7 0
2 years ago
Write an equation of the line that passes through the given point and is parallel to the given line.
9966 [12]

Answer : <em>Equation of line is</em> y=Equation of line is y=\frac{2}{3}x+\frac{-5}{3}

Step-by-step explanation:

Theory :

Equation of line is given as y = mx + c.

Where, m is slope and c is y intercepted.

Slope of given line : y = \frac{2}{3}x+1 is m= \frac{2}{3}

We know that line : y = \frac{2}{3}x+1 is parallel to equation of target line.

therefore, slope of target line will be \frac{2}{3}.

we write equation of target line as y= \frac{2}{3}x+c

Now, It is given that target line passes through point ( -5,-2)

hence, point ( -5,-2) satisfy the target line's equation.

we get,

y= \frac{2}{3}x+c

-2= \frac{2}{3} \times -5+ c

-5= \frac{-10}{3}+c

c= \frac{-5}{3}

thus, Equation of line is y=Equation of line is y=\frac{2}{3}x+\frac{-5}{3}

7 0
3 years ago
Help please !!!!!!!!
AlekseyPX

Answer:

Place the left of the dot on -5 and the right one on +7

That should do it :)

5 0
3 years ago
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