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ser-zykov [4K]
3 years ago
9

Outline how the engineer in the following scenario can create an

Engineering
1 answer:
kumpel [21]3 years ago
4 0
Cool that’s like very cool
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(Architecture) Sarah is an environmental activist. She frequently conducts various programs and activities in her community to p
ddd [48]

The council from which Sarah can obtain her building certification is;

<u><em>US Green Building Council</em></u>

  • We are told that Sarah is an environmental activist because she conducts a lot of programs to advocate for clean and sustainable environment.

Now, there is a program called LEED which is an acronym for <em>Leadership in </em>

<em>Energy and Environmental Design</em> standards that is necessary for those

that want to measure the greenness of buildings.

     This <em>LEED</em> program explained above is organized by an organization in

the United States of America (USA) known as US Green Building Council

(USGBC). This program is for everyone who wants to be a certified

environmental activist and thus i t is recommended that Sarah gets her

certification here.

Read more at; brainly.com/question/24611198

5 0
3 years ago
A steady tensile load of 5.00kN is applied to a square bar, 12mm on a side and having a length of 1.65m. compute the stress in t
Shtirlitz [24]

Answer:

The stress in the bar is 34.72 MPa.

The design factor (DF) for each case is:

A) DF=0.17

B) DF=0.09

C) DF=0.125

D) DF=0.12

E) DF=0.039

F) DF=1.26

G) DF=5.5

Explanation:

The design factor is the relation between design stress and failure stress. In the case of ductile materials like metals, the failure stress considered is the yield stress. In the case of plastics or ceramics, the failure stress considered is the breaking stress (ultimate stress). If the design factor is less than 1, the structure or bar will endure the applied stress. By the opposite side, when the DF is higher than 1, the structure will collapse or the bar will break.

we will calculate the design stress in this case:

\displaystyle \sigma_{dis}=\frac{T_l}{Sup}=\frac{5.00KN}{(12\cdot10^{-3}m)^2}=34.72MPa

The design factor for metals is:

DF=\displaystyle \frac{\sigma_{dis}}{\sigma_{f}}=\frac{\sigma_{dis}}{\sigma_{y}}

The design factor for plastic and ceramics is:

DF=\displaystyle \frac{\sigma_{dis}}{\sigma_{f}}=\frac{\sigma_{dis}}{\sigma_{u}}

We now need to know the yield stress or the ultimate stress for each material. We use the AISI and ASTM charts for steels, materials charts for non-ferrous materials and plastics safety charts for the plastic materials.

For these cases:

A) The yield stress of AISI 120 hot-rolled steel (actually is AISI 1020) is 205 MPa, therefore:

DF=\displaystyle\frac{34.72MPa}{205MPa}=0.17

B) The yield stress of AISI 8650 OQT 1000 steel is 385 MPa, therefore:

DF=\displaystyle\frac{34.72MPa}{385MPa}=0.09

C) The yield stress of ductile iron A536-84 (60-40-18) is 40Kpsi, this is 275.8 MPa, therefore:

DF=\displaystyle\frac{34.72MPa}{275.8MPa}=0.125

D) The yield stress of aluminum allot 6061-T6 is 290 MPa, therefore:

DF=\displaystyle\frac{34.72MPa}{290MPa}=0.12

E) The yield stress of titanium alloy Ti-6Al-4V annealed (certified by manufacturers) is 880 MPa, therefore:

DF=\displaystyle\frac{34.72MPa}{880MPa}=0.039

F) The ultimate stress of rigid PVC plastic (certified by PVC Pipe Association) is 4Kpsi or 27.58 MPa, therefore:

DF=\displaystyle\frac{34.72MPa}{27.58 MPa}=1.26

In this case, the bar will break.

F) You have to consider that phenolic plastics are used as matrix in composite materials and seldom are used alone with no reinforcement. In this question is not explained if this material is reinforced or not, therefore I will use the ultimate stress of most pure phenolic plastics, in this case, 6.31 MPa:

DF=\displaystyle\frac{34.72MPa}{6.31 MPa}=5.5

This material will break.

3 0
3 years ago
1. When jump starting a car, make sure it is in __________.
____ [38]

Answer:

Make sure both cars are in park or neutral with the parking brake engaged. This makes sure that all electrical functions (headlights, radios, etc.) are turned off.

8 0
3 years ago
A small object A is held against the vertical side of the rotating cylindrical container of radius r by centrifugal action. If t
xxMikexx [17]

Answer:

el radius es coeficiente por que determina la expresión

8 0
3 years ago
A. How is a decision matrix useful during the
Alinara [238K]

Answer:

The Decision Matrix

As you compare potential solutions to your design brief and the universal criteria for a good design, it may be obvious which solution is the best. ... A decision matrix is a chart with your requirements and criteria on one axis and the different solutions on the other.

5 0
3 years ago
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