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Ymorist [56]
2 years ago
6

Find m please help me i’ve been stuck on this problem for 30 minutes!!!

Mathematics
1 answer:
victus00 [196]2 years ago
8 0

6×+8=14 5×+2=7 14×7=98 ∆m=4.66

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Alan multiplies a 4-digit number by 36. How can you tell the
mafiozo [28]

The number of partial products Alan will have when he multiplies a 4-digit number by 36 is; 8 partial products.

First, we must establish that a 4-digit number will have 4 place values namely;

  • Thousands
  • Hundreds
  • Tens
  • Ones.

And since, 36 has 2 place values;

We can conclude that the number of partial products that Alan wil have is; 2× 4 = 8.

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8 0
2 years ago
Read 2 more answers
A sprinter who weighs 706 N runs the first 5.5 m of a race in 1.6 s, starting from rest and accelerating uniformly. What are the
zhenek [66]

Answer:

(a) Speed = 6.875 m/s

(b) Kinetic Energy = 1.70 kJ

(c) Average power =  1.06 kW

Step-by-step explanation:

Given:

d = 5.5 m

t = 1.6 s

W = 706 N

Part (a)

Using the equation of motion with the assumption of zero initial speed:

d = \frac{1}{2} ({v-0})t

5.5= \frac{1}{2} (1.6v)

The speed of the sprinter then become:

v = 6.875 m/s

Part (b)

Convert the weight of the sprinter to mass:

m = \frac{w}{g}

m = \frac{706}{9.8}

m = 72 kg

KE (Kinetic Energy) can then be calculated as:

KE = \frac{1}{2} mv^{2}

KE = \frac{1}{2} (72)(6.875)^{2}

KE = 1701.56 J = 1.70 kJ

Part (c)

The change of the kinetic energy is equivalent to the work done by the sprinter. The average power P is the rate of the work done and can be calculated as

P = \frac{KE}{t} \\\

P = \frac{1701.56}{1.6}

P = 1063.48 W = 1.06 kW

5 0
3 years ago
Which choice best reflects the overall sequence of
Grace [21]

Correct option is D. An unexpected result occurs during the initial phase of a study; the study is modified in response to this result and the results are interpreted and evaluated.

The writer begins this passage by stating that the ability of birds to fly has long been a source of debate among scientists.

The article then goes on to explain that when a group of students challenged Ken Dial to come up with new data on this hotly debated topic, he devised an experiment to study the evolution of flight by observing how baby Chukars learn to fly. Dial noted the unusual way the little Chukar "used its wings and legs cooperatively" to climb over hay bales during the experiment. Following that, he devised a series of experiments to investigate his discovery.

<h3>Below is the passage mentioned in the question is from Thor Hanson, Feathers by Thor Hanson - </h3>

" At field sites around the world, Ken Dial saw a

pattern in how young pheasants, quail, tinamous,

and other ground birds ran along behind their

parents. “They jumped up like popcorn,” he said,

5 describing how they would flap their half-formed

wings and take short hops into the air. So when a

group of graduate students challenged him

to come up with new data on the age-old

ground-up-tree-down debate, he designed a project

10 to see what clues might lie in how baby game birds

learned to fly.

.............................................................

Ken called the technique WAIR, for wing-assisted

incline running, and went on to document it in a

wide range of species. It not only allowed young

birds to climb vertical surfaces within the first few

weeks of life but also gave adults an energy-efficient

65 alternative to flying. In the Chukar experiments,

adults regularly used WAIR to ascend ramps steeper

than 90 degrees, essentially running up the wall and

onto the ceiling.

In an evolutionary context, WAIR takes on

70 surprising explanatory powers. With one fell swoop,

the Dials came up with a viable origin for the

flapping flight stroke of birds (something gliding

animals don’t do and thus a shortcoming of the

tree-down theory) and an aerodynamic function for

75 half-formed wings (one of the main drawbacks to the

ground-up hypothesis). "

To learn more about passages from the given link

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#SPJ4

7 0
1 year ago
Caitlin has $5 and $10 bills that are worth $675. She has twice as many $10 bills as $5 bills. How many of each type of bill doe
Lerok [7]

Caitlin has 27 $5 bills and 54 $10 bills.

Step-by-step explanation:

Given,

Worth of $5 and $10 bills = $675

Let,

Number of $5 bills = x

Number of $10 bills = y

According to given statement;

5x+10y=675    Eqn 1

She has twice as many $10 bills as $5 bills.

y=2x    Eqn 2

Putting value of y from Eqn 2 in Eqn 1

5x+10(2x)=675\\5x+20x=675\\25x=675

Dividing both sides by 25

\frac{25x}{25}=\frac{675}{25}\\x=27

Putting x=27 in Eqn 2

y=2(27)\\y=54

Caitlin has 27 $5 bills and 54 $10 bills.

Keywords: linear equation, substitution method

Learn more about substitution method at:

  • brainly.com/question/10699220
  • brainly.com/question/10703930

#LearnwithBrainly

7 0
3 years ago
A recipe calls for 2 3/4 cups of milk. if the recipe is tripled, how much milk is needed?
SSSSS [86.1K]
To be tripled means to be multiplied by 3. So multiply 2 3/4 by 3
2 3/4*3=8 1/4
Therefore the amount of milk needed is 8 1/4 cup
5 0
3 years ago
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