Describe one way to find the area of the figure below, given the dimensions. Solve for a challenge

Mathematics

1 answer:

tigry1 [53]3 years ago

8 0

Answer:

OK so you didnt put which numbers, but here is how you solve for area. Say if the legnth is 4 and the widght is 6. you have to do legnth times witgh, it this case 6x4 area is 24. Lxw=a

Step-by-step explanation:

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What property is this: 2 • 7 • 2 • 1 = (2 • 7) • (2 • 1)

Marta_Voda [28]

Commutative property

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3 years ago

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A kangaroo leaps a total distance of six feet with a maximum height of two feet. Write the equation representing the path of the

Serjik [45]

In order to find how long the the kangaroo's jump was, we are going to find out what the value of x is when y=0, because y=0 represents the kangaroo on the ground.
0 = -0.03(x - 14)2 + 6 Original equation with 0 substituted for y
0.03(x - 14)2 = 6 Add 0.03(x - 14)2 to each side
(x - 14)2 = 200 Divide both sides by 0.03
x - 14 = +/- 10√2 Take the square root of each side
x = 14 +/- 10√2 Add 14 5o each side
Because 10√2 is approximately 14.14, 14 - 10√2 is approximately 0. This makes sense because the kangaroo has not left the ground yet at 0 ft. The correct answer is 14 + 10√2, which is approximately 28.14 ft.
For part a, we want to use the distance that is halfway between the zeroes of the jump. That is the point halfway between 14 - 10√2 and 14 + 10√2. In other words, we need to use the value 10√2 (approx. 14.14) for x and solve for y.
y = -0.03(10√2 - 14)2 + 6 Write original equation with 10√2 substituted for y
y = -0.03(14.14 - 14)2 + 6 (Using approximation)
y = -0.03(0.14)2 + 6 Substitute (14.14 - 14 = 0.14)
y = -0.03(0.0196) + 6 Square 0.14
y = -0.000588 + 6 Multiply -0.03 times 0.0196
y = 5.999412 Add -0.00588 and 6
y = 6 Round
I went through all of the this work to show that the maximum point of the parabola (the highest point in the kangaroo's jump) is actually the point where the value being squared is 0 (14 - 14). The y-value of the vertex is 6. That is also the highest point in the jump.

The answers are:
a. 6 ft
b. 28.14 ft

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3 years ago

True or False (& Justify): If a ball is thrown horizontally from the top edge of a 150m building at a speed of 25 m/sec, the

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Answer:

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Step-by-step explanation:

The motion of the ball is a projectile motion, which consists of two independent motions:

- A uniform motion (constant velocity) along the horizontal direction

- A uniformly accelerated motion, with constant acceleration (acceleration of gravity) in the downward direction

Therefore we have to analyze the horizontal and vertical motion separately.

Along the horizontal direction, the velocity is constant during the motion, since there are no forces acting in this direction. So the horizontal velocity 3 seconds after the launch will be the same as the velocity at the launch:

$v_x = v_0 = 25 m/s$