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tatuchka [14]
3 years ago
13

Use Euler's formula to find the missing number.

Mathematics
2 answers:
irakobra [83]3 years ago
6 0
The answer is C 16 I believe
liraira [26]3 years ago
3 0

Answer: D. 18

Step-by-step explanation:

Euler's formula is Faces + Vertices = Edges + 2

Faces = Edges - vertices + 2

Faces = 39-23 + 2 = 18

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What’s the answer for 6?
horrorfan [7]
I'm not 100 percent sure but I think is e
6 0
3 years ago
50 POINTS
larisa [96]

Check the picture below.

how do we know?  well, notice h(t), starts off at 12, up up up reaches 47.84 then down down down, which is pretty much the trajectory of a flying object, by the time it gets to 44, is still going down.

now, let's look at g(t), starts off at 10, and goes up up up, never down, by the time it gets to 41, is still going up,

so at second 2, h(t) is 44 and going down, g(t) is 41 and going up, at 2.2 h(t) is 40.16, and g(t) is 44.1, between that lapse, h(t) became 44, 43, 42, 41, in the same lapse g(t) became 41, 42, 43, 44, so somewhere in those values h(t) = g(t).

what does the solution mean?  It's the seconds or the instant lapse when the first cannon ball was at the same height as the second cannonball.

3 0
3 years ago
Please Help me I’m begging you
eduard

Answer:

A

Step-by-step explanation:

4 0
2 years ago
What is a solutions of x^2-2x+10=0?​
Debora [2.8K]

Answer:

x = 1± 3i

Step-by-step explanation:

x^2-2x+10=0

We can complete the square to solve by subtracting 10 from each side

x^2-2x+10-10=-10

x^2 -2x = -10

We need to add (2/2) ^2  to each side or 1

x^2 -2x+1 = -10 +1

x^2 -2x+1 = -9

The left side factors into (x- (2/2) ) ^2

(x-1) ^2 = -9

Take the square root of each side

sqrt((x-1) ^2 =± sqrt(-9)

x-1 = ±sqrt(-1) sqrt(3)

Remember the sqrt(-1) = i

x-1 = ± 3i

Add 1 to each side

x-1+1 = 1± 3i

x = 1± 3i

8 0
2 years ago
How can I solve 2x+y=-3
Vladimir79 [104]

Answer:

If solving for x then x = -3/2 +y/2

If solving for y then y = -3-2x

Step-by-step explanation:

For x: Divide both sides by 2

For y: Subtract 2x from both sides of the equation

4 0
3 years ago
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