Answer:
I know it's a bit late, but the answer is C
Step-by-step explanation:
Got it right on edge
Given:
A fair die is rolled.
It pays off $10 for 6, $7 for a 5, $4 for a 4 and no payoff otherwise.
To find:
The expected winning for this game.
Solution:
If a die is rolled then the possible outcomes are 1, 2, 3, 4, 5, 6.
The probability of getting a 6 is:
The probability of getting a 5 is:
The probability of getting a 4 is:
The probability of getting other numbers (1,2,3) is:
We need to find the sum of product of payoff and their corresponding probabilities to find the expected winning for this game.
Therefore, the expected winnings for this game are $3.50.
Answer:
B.
Step-by-step explanation:
Since they are talking about the weight of the box increasing I think (correct me if I am wrong) that the answer would be w.
I hope this helps :)
Answer:
y = (6/5)x -2
Step-by-step explanation:
Answer:
Step-by-step explanation:
i² = -1
i⁵ = i² * i² * i
= (-1) * (-1) * i
i⁵ = i
i²⁵ = i ⁵ˣ⁵ = (i⁵)⁵
= (i)⁵
= i