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PSYCHO15rus [73]
3 years ago
10

Write an equation of the line parallel to y=8x-1 that contains the point (-6,2)

Mathematics
2 answers:
s2008m [1.1K]3 years ago
5 0
Parallel lines have the same slope so you use the 8 from the equation and plug in with your points to point slope form equation 

Charra [1.4K]3 years ago
4 0

Answer:

y=8x+50

Step-by-step explanation:

We are looking for the same line but with a different y-intercept.

Equation of a line in its Slope–intercept form is given by:

y=mx+b

Where:

m=slope\\b=y-intercept

We know the slope which is the same of the line:

y=8x-1

So:

m=8

And we know a point:

(x_o,y_o)=(-6,2)

Let's find the equation of the line parallel to y=8x-1 using the data provided and the next equation:

y-y_o=m(x-x_o)\\\\y-2=8(x-(-6))\\\\y-2=8x+48\\\\y=8x+50

Now let's verify the result.

First, does it contains the point (-6,2)?

Evaluate the function for x=-6:

y=8(-6)+50\\\\y=-48+50\\\\y=2

Second, is it parallel to y=8x-1?

Try to solve the 2x2 system of equations:

8x-y=1\hspace{3}(1)\\8x-y=-50\hspace{3}(2)

Using elimination method:

(1) - (2)

8x-8x-y-(-y)=1-(-51)\\\\0=-51

The system has no solutions. Hence the lines are parallel.

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solong [7]

Answer:

The end of the flagpole is 50.79 ft away from the base of the pole.

Step-by-step explanation:

The problem is represented by the diagram below.

The broken flagpole forms the shape of a right angled triangle. We need to find one of the sides of the triangle, the adjacent (x).

The hypotenuse is the broken part of the flagpole (53 ft), while the opposite is the part of the flagpole that is still stuck to the ground (28 ft).

Using Pythagoras theorem, we have that:

hyp^2 = adj^2 + opp^2

=> 53^2 = x^2 + 28^2

3364 = x^2 + 784\\\\=> x^2 = 3364 - 784\\\\x^2 = 2580\\\\x = \sqrt{2580}\\ \\x = 50.79 ft

The end of the flagpole is 50.79 ft away from the base of the pole.

7 0
3 years ago
Name the value of each 2 in 222,222
Anvisha [2.4K]
Hundred thousands
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3 0
3 years ago
Read 2 more answers
An online camping supplies outlet charges $14 for a canteen,
Vedmedyk [2.9K]

Answer:

Part A: 14x + 2

Part B: CJ's order is $30, and Cameron's order is $58.

Step-by-step explanation:

<u>Part A:</u> The total cost of the order would be $14 multiplied by the amount of canteens, plus the shipping price of $2. This is what my expression represents.

<u>Part B:</u>

CJ's Order:

14(2) + 2 =

28 + 2

$30

Cameron's Order:

14(4) + 2 =

56 + 2 =

$58

Hope this helps! :D

3 0
2 years ago
The measure of c is .
mina [271]

Answer:

c^2=a^2+b^2

c^2=6^2+8^2

c^2=36+64

c=10

but still do not understand why peoples are asking that basic

4 0
2 years ago
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10m^3 of air weigh 13 kg.
Lemur [1.5K]

49.686‬ kg

Step-by-step explanation:

Since the density of the air remains constant in the question

We can represent this equation as a ratio;

10 m³ =  13 kg

(4.2 * 3.5 * 2.6)  m³ = ? (x) kg

4.2 * 3.5 * 2.6 = 38.22

We cross multiply

38.22 * 13 = 10 * x

X = 496.86‬ /10

X = 49.686‬

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