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2 years ago

10

Do number 5 pleaseee

1 answer:

swat322 years ago

6 0

Answer:

A

Step-by-step explanation:

16 × 2 = 32

20 × 2 = 40

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Gianna is paid $90 for 5 hours of work.

Alisiya [41]

Answer:

a. $144

b. about 34 hours

Step-by-step explanation:

If Gianna is paid $90 dollars for 5 hours of work, that means that she is paid $18 an hour. So, 18x33 is 594, which means that 18x34 is $612.

6 0

3 years ago

The local library lends an average of 68.24 books to readers each day. What is the average number of books lent to readers in a

Morgarella [4.7K]

The local library lends an average books per day = 68.24

We know there are 7 days in a week

To find the the average number of books lent to readers in a week, we multiply the number of days in a week by average number of books per day.

let x be the average number of books per week

x= 68.24 * 7

x= 477.68

The local library lends an average of 477.68 books to readers every week.

7 0

3 years ago

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What is 0.194 repeating as a fraction

laiz [17]

Convert to a fraction by placing the decimal number over a power of 10. So the awnser is 97/500
I hope I helped you

4 0

4 years ago

Solve equation by using the quadratic formula.<br> 15x^2 + 13x = 0

MariettaO [177]

Answer:

0 and - 13/15

Step-by-step explanation:

3 0

3 years ago

Match each spherical volume to the largest cross sectional area of that sphere

zlopas [31]

Answer:

Part 1) $324\pi\ units^{2}$ ------> $7,776\pi\ units^{3}$

Part 2) $36\pi\ units^{2}$ ------> $288\pi\ units^{3}$

Part 3) $81\pi\ units^{2}$ ------> $972\pi\ units^{3}$

Part 4) $144\pi\ units^{2}$ ------> $2,304\pi\ units^{3}$

Step-by-step explanation:

we know that

The largest cross sectional area of that sphere is equal to the area of a circle with the same radius of the sphere

Part 1) we have

$A=324\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

so

$324\pi=\pi r^{2}$

Solve for r

$r^{2}=324$

$r=18\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=18\ units$

substitute

$V=\frac{4}{3}\pi (18)^{3}$

$V=7,776\pi\ units^{3}$

Part 2) we have

$A=36\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

so

$36\pi=\pi r^{2}$

Solve for r

$r^{2}=36$

$r=6\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=6\ units$

substitute

$V=\frac{4}{3}\pi (6)^{3}$

$V=288\pi\ units^{3}$

Part 3) we have

$A=81\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

so

$81\pi=\pi r^{2}$

Solve for r

$r^{2}=81$

$r=9\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=9\ units$

substitute

$V=\frac{4}{3}\pi (9)^{3}$

$V=972\pi\ units^{3}$

Part 4) we have

$A=144\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

so

$144\pi=\pi r^{2}$

Solve for r

$r^{2}=144$

$r=12\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=12\ units$

substitute

$V=\frac{4}{3}\pi (12)^{3}$

$V=2,304\pi\ units^{3}$

5 0

3 years ago

Read 2 more answers