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Schach [20]
3 years ago
12

The midpoint of AB is M(2, -1). If the coordinates of A are (1,6), what are the

Mathematics
1 answer:
VashaNatasha [74]3 years ago
5 0

Answer:

work is attached and shown

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Movies Tonight is a typical video and DVD movie rental outlet for home-viewing customers. During the weeknight evenings, custome
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the probability having no customers are in the system is 0.375

Step-by-step explanation:

The computation of the probability having no customers are in the system is as follows;

Given that the arrival rate is 1.25 customers per minute

The Service rate is 2 customers per minute

Based on the above information, the probability is

=P_0\\\\=(1-\frac{\lambda }{\mu })\\\\=(1-\frac{1.25}{2})\\\\=1-0.625\\\\= 0.375

Hence, the probability having no customers are in the system is 0.375

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3 years ago
a neophyte is a beginner. on the first day of classes, 28,000 students arrived at the university campus. if three-sevenths were
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16 ,000  students are not neophytes.

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F(x)=9x^2+7x-13 describe the behavior
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hob

Step-by-step explanation:

jbibou

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Two trains leave stations 374 miles apart at the same time and travel toward each other. One train travels at 95 miles per hour
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2 hrs and 12 min or 2.2 hrs

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Suppose a couple planned to have three children. Let X be the number of girls the couple has.
sesenic [268]

Answer:

a) {GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) {0,1,2,3}

c)

P(X=2) = \dfrac{3}{8}

d)

P(\text{3 boys}) = \dfrac{1}{8}

Step-by-step explanation:

We are given the following in the question:

Suppose a couple planned to have three children. Let X be the number of girls the couple has.

a) possible arrangements of girls and boys

Sample space:

{GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) sample space for X

X is the number of girls couple has. Thus, X can take the values 0, 1, 2 and 3 that is 0 girls, 1 girl, 2 girls and three girls from three children.

Sample space: {0,1,2,3}

c) probability that X=2

P(X=2)

That is we have to compute the probability that couple has exactly two girls.

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

Favorable outcome: {GGB, GBG, BGG}

P(X=2) =\dfrac{3}{8}

d) probability that the couple have three boys.

Favorable outcome: {BBB}

P(BBB) = \dfrac{1}{8}

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3 years ago
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