According to law of cosines the length of RQ can be written as
.
Given the length PR is 6 , the length of RQ is p, the length of PQ is 8 and the angle RPQ is 39 degrees.
A length of the triangle can be written as according to law of cosines if sides are given and one angle is 
We have to just put the values in the above equation.
as
.
p is the side opposite to angle given , the length of other sides are 6 and 8 and angle is 39 degrees.
Hence the side can be written as according to law of cosines if the angle is 39 degrees is as
.
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The first, third, and sixth are correct.
We are given the description of a diagram where the base of a parallelogram lies on the x-axis with the left vertex on the origin. We are also given the three consecutive coordinates of the vertices which are
(h, j ), (0, 0), and (k, 0)
Based on the coordinates, the point (h, j) is j units from the y-axis
Answer:
16 holes in ones
Step-by-step explanation:
I just did the guiz and got that one right
Replace n with 9 :
7 × 9 - 3 = 60
the answer is C.60