Slightly basic is the anwser
The answer is 8 (anaphase 1), 8 (anaphase 2), 4 (metaphase 2).
Meiosis is a cell division which results in a reduction of the number of chromosomes in half and it consists of meiosis I and meiosis II.
Before meiosis I begins, the cell is diploid (2n) and there are 8 chromosomes. In anaphase I<span>, the sister chromatids separate from each other to the opposite sides of the cells, and after that, there are 8 chromosomes and 16 chromatids. After telophase I, there are, however, <u>4 chromosomes that enter meiosis II</u>.
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Meiosis II is similar to mitosis. So, in metaphase II there is the same number of chromosomes - 4 chromosomes. But, the chromosome number must double so in anaphase II there will be in total 8 chromosomes - 4 chromosomes at the one side of the cell and the 4 on the other side. After telophase II, there are 4 chromosomes.
The correct answer for the question that is being presented above is this one: "6H2O, NADP, light energy, 18ADP + Pi." The input of the light-dependent reactions, labeled X is that <span>6H2O, NADP, light energy, 18ADP + Pi.</span>
Answer - Speciation
Reasoning - Pretty much what has happen was the two species has evolved over the course of evolution if you want to put it that way why the are incapable of breeding.
Explanation:
In a DNA molecule, Adenine forms hydrogen bonds with Thymine and Cytosine forms hydrogen bomds with Guanine.
However in mRNA, Thymine becomes Uracil (T => U)
Therefore every A in the DNA sequence becomes U,
every T in the DNA sequence becomes A,
every C in the DNA sequence becomes G,
every G in the DNA sequence becomes C.
The answer is A.
