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Nataliya [291]
3 years ago
14

Can someone help me?

Mathematics
1 answer:
Eva8 [605]3 years ago
4 0

9514 1404 393

Answer:

  see below

Step-by-step explanation:

This is all about number sense: ordering and naming numbers. If you know your multiplication tables and a few key vocabulary words, that's all you need.

1a. perfect square

1b. irrational number

1c. greater than

__

2a. less than; greater than

2b. perfect square

2c. approximation

__

3a. square root

3b. square root

3c. approximation

3d. order; less than; less than

_____

When you fill in the blanks, the statements pretty much explain themselves.

__

<em>Additional comment</em>

For positive numbers, square and square root are operations that preserve order. That is, the square of a larger number is larger than the square of a smaller number. Likewise, the square root of a larger number is larger than the square root of a smaller number. Here, ...

  81 > 64 > 44   ⇔   √81 > √64 > √44.

If a number is not a perfect square (a number multiplied by itself), then its square root is irrational.

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Learn how to find the distance between two points by using the distance formula, which is an application of the Pythagorean theorem. We can rewrite the Pythagorean theorem as d=√((x_2-x_1)²+(y_2-y_1)²) to find the distance between any two points.

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Answer:

d=3\sqrt{2}\ units

Step-by-step explanation:

<u><em>The complete question is</em></u>

Line L contains points (3, 5) and (7, 9). Points P has coordinates (2, 10). Find the distance from P to L

step 1

Find the equation of the line L contains points (3,5) and (7,9)

<em>Find the slope</em>

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

substitute the given values

m=\frac{9-5}{7-3}

m=\frac{4}{4}=1

<em>Find the equation of the line in point slope form</em>

y-y1=m(x-x1)

we have

m=1\\point\ (3,5)

substitute

y-5=(1)(x-3)

isolate the variable y

y=x-3+5

y=x+2 -----> equation A

step 2

Find the equation of the perpendicular line to the given line L  that passes through the point P

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal

so

The slope of the given line L  is m=1

The slope of the line perpendicular to the given line L  is

m=-1

<em>Find the equation of the line in point slope form</em>

y-y1=m(x-x1)

we have

m=-1\\point\ (2,10)

substitute

y-10=-(x-2)

isolate the variable y

y=-x+2+10

y=-x+12 ----> equation B

step 3

Find the intersection point equation A and equation B

y=x+2 -----> equation A

y=-x+12 ----> equation B

solve the system by graphing

The intersection point is (5.7)

see the attached figure

step 4

we know that

The distance from point P to the the line L is equal to the distance between the point P and point (5,7)

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

(2,10) and (5,7)

substitute

d=\sqrt{(7-10)^{2}+(5-2)^{2}}

d=\sqrt{(-3)^{2}+(3)^{2}}

d=\sqrt{18}\ units

simplify

d=3\sqrt{2}\ units

see the attached figure to better understand the problem

6 0
3 years ago
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