<span>25 years: No Payment, but total is 250000
6 months earlier. Payment of "P". It's value 1/2 year later is P(1+0.03)
6 months earlier. Payment of "P". It's value 1 year later is P(1+0.03)^2
6 months earlier. Payment of "P". It's value 1½ years later is P(1+0.03)^3
6 months earlier. Payment of "P". It's value 2 years later is P(1+0.03)^4
</span><span>We need to recognize these patterns. Similarly, we can identify the accumulated value of all 50 payments of "P". Starting from the last payment normally is most clear.
</span>
<span>P(1.03) + P(1.03)^2 + P(1.03)^3 + ... + P(1.03)^50
That needs to make sense. After that, it's an algebra problem.
P[(1.03) + (1.03)^2 + (1.03)^3 + ... + (1.03)^50]
</span>
P(<span><span>1.03−<span>1.03^51)/(</span></span><span>1−1.03) </span></span>= <span>250000</span>
Answer:
$50
Explanation:
Jim buys a 5% bond
The amount is $100
The market interest rate increases to 10%
Therefore the price at which the bond cann be sold is calculated as follows
= 5×100
= 500×0.01
= 50
Hence it can be sold for $50
Answer:
If American produces the new compound, profit will increase by $88,000
Explanation:
increase in selling price = selling price of new variant of chemical - selling price of chemical compound
= $83 - $52
= $31
Net increase in profit = total increase in selling price - additional processing cost
= $31*8000 - $160000
= $248000 - $160000
= $88,000
Therefore, If American produces the new compound, profit will increase by $88,000.
net increase in profit =
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