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2 years ago

1. Determine whether the following numbers could be the sides of a right triangle. Show your work.

Mathematics

1 answer:

sergejj [24]2 years ago

7 0

Answer:

B 17,15,8

Step-by-step explanation:

8sqrd+15sqrd=17sqrd

64+225=289

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Solve x2−4x−12=0 by completing the square. A x=−2 B x=−6 or x=2 C x=−2 or x=6 D x=−6

MrRissso [65]

Answer:

B x=-6

x=2

Step-by-step explanation:

8 0

2 years ago

What is the slope of (-4,6) and (2,-5)

Dominik [7]

Answer:

-11/6

Step-by-step explanation:

Slope can be found with this equation:

(y₁ - y₂) / (x₁ - x₂)

What this essentially tells us to do is to put one set of the x and y coordinates into x₁ and y₁, respectfully. Then, put the other set of x and y points as x₂ and y₂.

With this scenerio, we can substitute the given points into the formula.

(6 - (-5)) / (-4 - 2) =

(6 + 5 ) / (-6) =

11 / (-6) =

-11/6

The slope is - 11/6

4 0

3 years ago

Read 2 more answers

The weights of certain machine components are normally distributed with a mean of 8.04 g and a standard deviation of 0.08 g. Fin

NISA [10]

Answer:

The bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.

Step-by-step explanation:

We are given that

Mean, $\mu=8.04 g$

Standard deviation, $\sigma=0.08g$

We have to find the two weights that separate the top 3% and the bottom 3%.

Let x be the weight of machine components

$P(Xx_2)=0.03$

$P(X$

=0.03

From z- table we get

$P(Z1.88)=0.03$

Therefore, we get

$\frac{x_1-8.04}{0.08}=-1.88$

$x_1-8.04=-1.88\times 0.08$

$x_1=-1.88\times 0.08+8.04$

$x_1=7.8896$

$\frac{x_2-8.04}{0.08}=1.88$

$x_2=1.88\times 0.08+8.04$

$x_2=8.1904$

Hence, the bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.

5 0

2 years ago

Write a sentence describing the meaning of the statement c(2)=40

aev [14]

Step-by-step explanation:

A number,c times two equal forty.

5 0

2 years ago

Anybody pls help me. Plus, working. Thank you

Umnica [9.8K]

I hope my answer can help you.

5 0

3 years ago