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Lunna [17]
3 years ago
11

Why the fraction equivalent of 0.1 is 1/10?

Mathematics
2 answers:
Dahasolnce [82]3 years ago
4 0

Answer:

It is equivalent because of the way you solved it.

Step-by-step explanation:

Maurinko [17]3 years ago
3 0

Answer:

To try to explain, I’m going to give you a new way to read fractions. For a/b, say “b of them make a”. For example, 1/3 is “3 of them make 1”, because 1/3+1/3+1/3=1. 2/7 is “7 of them make 2”, because 2/7+2/7+2/7+2/7+2/7+2/7+2/7=2. This works for whole numbers a and b.

You can change the numbers like so: “3 of them make 1” is the same as “6 of them make 2”, and so 1/3=2/6. Similarly “7 of them make 2” is the same as “14 of them make 4” so 2/7=4/14. “2 of them make 12” is the same as “1 of them makes 6”, so 12/2=6/1=6.

Now 1/0.1 is “0.1 of them make 1”. Whatever “they” are, you only need 0.1 of them to make 1, so “they” must be bigger than 1. How much bigger? Following the pattern, “0.1 of them make 1” is the same as “0.2 of them make 2”, “0.5 of them make 5”, and “1 of them makes 10”. So 1/0.1=10

Step-by-step explanation:

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What is 9/16 closest to 0,1/2, or 1 and why?
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7 0
3 years ago
12% of what number is 36
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Read 2 more answers
Life rating in Greece. Greece has faced a severe economic crisis since the end of 2009. A Gallup poll surveyed 1,000 randomly sa
elena-s [515]

Answer:

a

        The population parameter of interest is the true proportion of Greek who are suffering

    While the point estimate of this parameter is  proportion of those that would rate their lives poorly enough to be considered "suffering". which is 25%  

b

   The condition  is met

c

   The  95% confidence interval is   0.223 <  p  < 0.277

d

      If the confidence level is increased which will in turn reduce the level of significance but increase the critical value(Z_{\frac{\alpha }{2} }) and this will increase the margin of error( deduced from  the formula for margin of error i.e  E \ \alpha \  Z_{\frac{\alpha }{2} } ) which will make the confidence interval wider

e

  Looking at the formula for margin of error if the we see that if the  sample size is increased the margin of error will reduce making the  confidence level narrower

Step-by-step explanation:

From the question we are told that

    The sample size is  n  =  1000

     The  population proportion is  \r p  = 0.25

     

Considering question a

   The population parameter of interest is the true proportion of Greek who are suffering

    While the point estimate of this parameter is  proportion of those that would rate their lives poorly enough to be considered "suffering". which is 25%  

Considering question b

The condition for constructing a confidence interval is

        n *  \r p >  5\  and  \   n(1 - \r p ) >5

So  

        1000 *  0.25 > 5 \  and \  1000 * (1-0.25 ) > 5

         250  > 5 \  and \  750> 5

Hence the condition  is met

Considering question c

    Given that the confidence level is  95%  then  the level of significance is mathematically evaluated as

          \alpha  =  100 - 95    

          \alpha  =  5 \%

          \alpha  =  0.05

Next we obtain the critical value of \frac{\alpha }{2} from the normal distribution table, the value is  

              Z_{\frac{\alpha }{2} }  =  1.96        

Generally the margin of error is mathematically represented as

         E =  Z_\frac{ \alpha }{2}  *  \sqrt{ \frac{\r p (1 - \r p ) }{n} }

substituting values

         E =  1.96  *  \sqrt{ \frac{ 0.25 (1 - 0.25 ) }{ 1000} }

         E =  0.027

The  95% confidence interval is mathematically represented as

            \r p  - E  <  p  <  \r p  + E

substituting values  

           0.25 -  0.027  <  p  < 0.25 + 0.027

substituting values

           0.223 <  p  < 0.277

considering d

  If the confidence level is increased which will in turn reduce the level of significance but increase the critical value(Z_{\frac{\alpha }{2} }) and this will increase the margin of error( deduced from  the formula for margin of error i.e  E \ \alpha \  Z_{\frac{\alpha }{2} } ) which will make the confidence interval wider

considering e

     Looking at the formula for margin of error if the we see that if the  sample size is increased the margin of error will reduce making the  confidence level narrower

   

5 0
3 years ago
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