Answer:
4x-y+1=0
Step-by-step explanation:
here,given equation of a line id
4x-y-2=0.. eqn(i)
equation of any line parallel to line (i) is
4x-y+k=0...eqn(ii)
since, the line(ii) passes through (1,5)[replacing x=1 and y=5 in eqn(ii), we get]
4*1-5+k=0
or, 4-5+k=0
or,-1+k=0
•°•k=1
substituting the value of k=1 in eqn(ii),
4x-y+1=0 is the required equation of the line.
Answer:
The first error that Tomas made was added 6 to both sides of the equation instead of subtracting 6
Step-by-step explanation:
Let
x ----> represents the number of pounds of granola
y ----> represents the number of pounds of walnuts
we know that
The linear equation that represent this scenario is
2x+6y=12 -----> equation A
x=3 -----> equation B
substitute equation B in equation A and solve for y
2(3)+6y=12
6+6y=12
Subtract 6 both sides
6+6y-6=12-6
6y=6
Divide by 6 both sides
6y/6=6/6
y=1
so
The number of pounds of walnuts is 1
therefore
The first error that Tomas made was added 6 to both sides of the equation instead of subtracting 6
Answer:
hghjghgjh
Step-by-step explanation:
