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Tju [1.3M]
3 years ago
6

Use a graphing calculator to sketch the graph of the quadratic equation, and then state the domain and range

Mathematics
2 answers:
yKpoI14uk [10]3 years ago
8 0

Domain: all the real numbers  

Range: y ≤ 9/5

i hope u can see the attached graph! :)

MAVERICK [17]3 years ago
3 0

Answer:

a)

Step-by-step explanation:

vertex is at (-0.4, 1.8) so range must be less than or equal to 1.8

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Jim and Krutika are marking exam papers. Each set takes Jim 50 minutes and Krutika 1 hour. Express the times Jim and Krutika tak
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the length of a small leg of a 30 degree, -60 degree, -90 degree triangle is 3. what is the perimeter of the triangle.
BigorU [14]
Did you mean "small" or did you mean "shortest?"  

Let's assume that the shortest side has length 3.  This would be opposite the 30 degree angle.  We can form and solve an equation of ratios to solve this problem.  Since this is a 30-60-90 degree triangle, the perimeter could be 1x + sqrt(3)x + 2x.  1x is the shortest side, so 1x = 3, and x=3.

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3 years ago
Simplify 8(7x – 1) + 4(x + 5).
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4 0
3 years ago
A circle has its center at (6,-3). One point on the circle is (3, 1).
Komok [63]

Answer: A (10,-6)

Step-by-step explanation:

<u>step 1</u>:-  The equation of the circle is given center and radius is

(x-h)^{2} +(y-k)^{2} = r^{2}

<u>Step 2</u>:-

A circle has its center at (6,-3) and point on the circle is (3,1),Now

we have find radius from center to the given point on the circle

The distance of two points are

\sqrt{(x_{2}-x_{1})^2 +(y_{2}-y_{1} )^2  }

\sqrt{(1-(-3))^2+(3-6)^2}

\sqrt{25}

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<u>step 3</u>:-

The equation of the circle having center and radius is

(x-6)^{2}+(y+3)^2=5^{2}

verification:

This circle is passing through the point (10,-6)

(10-6)^{2}+(-6+3)^2=25

25 =25

There fore the another point that lies on the circle is (10,-6).

3 0
3 years ago
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