so taking the point T(13,1.6) and the point V(5.4,3.7) we move from point T(13,1.6) to the point V(5.4,3.7) the x-coordinate increases by ( 13-5.4)=7.6 and the y- coordinate decreases by ( 1.6-3.7)=(-2.1). now we have 7.6 and -2.1. we find the squares of this numbers and add so we have 7.6 giving us 57.76 and -2.1 giving us 4.41. now we add both 57.76+4.41=62.17. and we find the square roots √62.17 which will give us 7.884. and therefore the distance between the two point is 7.884
