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igor_vitrenko [27]
3 years ago
14

HELP I NEED HELP ASAP

Mathematics
1 answer:
Semmy [17]3 years ago
5 0

Answer:

B they equations i are múltiple

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Jehehwjjqhshsv behaves gaggwg wj. Wgywhw
bixtya [17]

Ummm... Are you ok? Please retype this lol

3 0
3 years ago
Read 2 more answers
A company is constructing an open-top, square-based, rectangular metal tank that will have a volume of 64 ft3. what dimensions y
Doss [256]

To solve this problem you must apply the proccedure shown below:

1. You must use the formula for calculate the surface area and the volume of the tank:

1) SA=x^{2} +4xy\\ 2) V=x^{2} y\\ 64=x^{2} y

2. Solve for y in the second equation and substitute it into the first one.Then, you have:

y=\frac{64}{x^{2}}  \\ SA=x^{2} +4x(\frac{64}{x^{2}})

3. Now, derivate:

SA'=2x-256x^{-2} \\ 2x-256x^{-2}=0

4. When you solve for x, you obtain:

2x^{3}-256=0\\ x=\sqrt[3]{\frac{256}{2}}  \\ x=5.03

5. Now, you must calculate y:

y=\frac{64}{(5.03)^{2}} \\ y=2.52

Therefore, the dimensions are:

The sides of the base of the tank: 5.03 feet

The height of the tank: 2.52 feet

8 0
3 years ago
The sum of two numbers is 436. The larger number is 3 times the smaller number. What are the numbers?
wolverine [178]
The numbers are 109 and 327. Hope it helps!
5 0
3 years ago
X(t) = t^3 - 12t^2 + 36t
r-ruslan [8.4K]
Yes you have the right idea. You find the derivative to get the velocity function and then determine when the velocity is zero. That turns out to be at t = 2 and t = 6. Both are correct. The final answer is correct.

The only flaw I see is that you wrote 
x'(t) = 3y^3 - 24t + 36
on line 2 when it should be
x'(t) = 3t^2 - 24t + 36

Other than that it looks perfect.

5 0
3 years ago
Puadratic Relations 1
In-s [12.5K]

Answer is in the photo. I can only upload it to a file hosting service. link below!

tinyurl.com/wpazsebu

4 0
3 years ago
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