Answer:
The answer is A
Step-by-step explanation:
this answer is helpful to my peers, because i literally just gave them what they were looking for.
Like all problems that involve images within the question, we should definitely try to draw this out. In the picture above, I have done this.
Now, we can see that this is just a simple proportion problem. For every 2.5 cm of height of the flower, we are 2 cm from the opening, or aperture. For every 20 cm of height, how far are we? We can set up the problem like this:
20 ............2.5
-------- = ---------
...x ............. 2
where x is the unknown distance to the aperture from the flower. Now, we just need to get x by itself. A typical way of solving something like this is by doing "butterfly multiplication" which is really just a shortcut haha. Anyway, I can rewrite that equation ^ as:
20×2 = 2.5 × x
Then, to solve for x, we would divide both sides by 2.5. (If you don't know why that is, please let me know and I'll elaborate).
We would then have:
20×2
------- = x
2.5
Which then simplifies to:
x = 16
Try using the same logic for your second question, and if you get stuck, I'd be happy to help! please let me know if any of this doesn't make sense. :)
I believe the answer is 5. Hope this was right for you.
Hi there!
I can see why you've posted a question like this here - For adding, subtracting, multiplying, or dividing fractions by whole numbers can be difficult to come out with a precise answer, so let me make it look easier for you!
So, the steps are:
Smush the 2 (whole number) and the 2 (the numerator of the fraction) together on top so its (2)(2) over 6. I can show you what I mean, if you'd like.
This is what it should look like.
Now, what is 2 times 2? You can use a calculator for this part.

Now, we can get to the last part, my favorite one!
Simplify
down to
.
How did we do it? EASY!
See what number does evenly into both numerators and denominators. In this case, 2 goes into 4 twice, and 2 goes into 6 three times, so we're left with our beautiful answer
.
That wasn't so bad, was it? You can use this as a guide for figuring out math problems like these, in case you're stuck again. But just in case, message me if you need anymore help! :D