Answer: 240
180×100=18,000
18,000÷75=240
to check
.75×240=180
I hope this is good enough:
Answer:
A
because range is all values of Y but in negative side it is infinity but in positive side range is 4
Terry, Kevin and Barry have a total of 215 marbles.=> Terry has 20 marbles more than Barry = x + 20=> Kevin has 10 marbles more than Terry = (x + 20) + 10=> Barry = xSolutions:=> x + x + 20 + x + 20 + 10 = 215=> 3x + 50 = 215=> 3x = 215 - 50=> 3x = 165=> 3x / 3 = 165 / 3=> x = 55Barry have = 55Terry = 55 + 20 = 75<span>Kevin => 75 + 10 = 85</span>
y = 9ln(x)
<span>y' = 9x^-1 =9/x</span>
y'' = -9x^-2 =-9/x^2
curvature k = |y''| / (1 + (y')^2)^(3/2)
<span>= |-9/x^2| / (1 + (9/x)^2)^(3/2)
= (9/x^2) / (1 + 81/x^2)^(3/2)
= (9/x^2) / [(1/x^3) (x^2 + 81)^(3/2)]
= 9x(x^2 + 81)^(-3/2).
To maximize the curvature, </span>
we find where k' = 0. <span>
k' = 9 * (x^2 + 81)^(-3/2) + 9x * -3x(x^2 + 81)^(-5/2)
...= 9(x^2 + 81)^(-5/2) [(x^2 + 81) - 3x^2]
...= 9(81 - 2x^2)/(x^2 + 81)^(5/2)
Setting k' = 0 yields x = ±9/√2.
Since k' < 0 for x < -9/√2 and k' > 0 for x >
-9/√2 (and less than 9/√2),
we have a minimum at x = -9/√2.
Since k' > 0 for x < 9/√2 (and greater than 9/√2) and
k' < 0 for x > 9/√2,
we have a maximum at x = 9/√2. </span>
x=9/√2=6.36
<span>y=9 ln(x)=9ln(6.36)=16.66</span>
the
answer is
(x,y)=(6.36,16.66)
Answer:
$64 is the answer
Step-by-step explanation:
If I am correct the x and y values are the ones values of the overall $60 so if you on the x axis to where the 6 is it matches up with the 4 on the y axis so therefore the answer must be $64.
I hope this helps
