Question

The distance between two points is 6_/6.One endpoint is (4,-1). It is known that the y-coordinate of the other endpoint is 9.

Answer 1

The x-coordinate of the given endpoint will be "$x = 4 \pm 2\sqrt{29}$".

According to the question,

The end points are:

• $(x_1,y_1) = (4,-1)$
• $(x_2, y_2) = (x,9)$

Distance,

• $6\sqrt{6}$

As we know,

The distance formula,

→ $Distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

By substituting the values, we get

→         $6\sqrt{6} = \sqrt{(x-4)^2+(9+1)^2}$

→          $216= (x-4)^2+100$

→   $(x-4)^2 = 116$

→       $x-4 = \pm \sqrt{116}$

→       $x-4=\pm 2\sqrt{29}$

→             $x = 4 \pm 2\sqrt{29}$                

Thus the above answer is right.  

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