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fredd [130]
3 years ago
13

4) To run program short cut​

Computers and Technology
1 answer:
quester [9]3 years ago
6 0

Answer:

Run Dialog

Open it by pressing WinKey+R. In the Run dialog, type the name of a program's .exe file and press Enter to launch it.

Explanation:

Please give me brainlist and follow

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Write a function named shareALetter that takes one parameter, wordList – a list of words. Create and return a dictionary in whic
Arte-miy333 [17]
Can u send anything to understand it
7 0
3 years ago
Chapter 20 reading and vocab review
aev [14]

Answer:

Essentially additive editing and stringing “the good stuff” together, whereas subtractive is more about stringing all your raw footage together and “removing the bad stuff”

Additive editing feels confident and concerned with the pursuit of a specific, existing vision. And it’s faster. Subtractive editing feels like a deeper listening to what the footage is saying, and holding on to many potential permutations.

Explanation:

Addictive editing -  creating a program from raw footage by starting by starting with nothing and adding selected components

Subtraction editing  - creating a program by removing redundant or poor quality material from the original footage

7 0
2 years ago
1. Write a program that declares an array named alpha with 50 components of the type double. Initialize the array so that the fi
Aleksandr [31]

Answer:

Explanation:

1. Write a program that declares an array named alpha with 50 components of the type double. Initialize the array so that the first 25 components are equal to the square of the counter (or index) variable and the last 25 components are equal to three times the index variable.  

  double alpha[50];

   for (int i=0;i<25;i++)

   {

       alpha[i]=i*i;

       alpha[i+25]=(i+25)*3;

  }

2. Output the array so that exactly ten elements per line are printed.  

   for (int i=0;i<50;i++)

   {

       cout<<i+1<<". "<<alpha[i]<<" ";

       if (((i+1)%10)==0)

       {

           cout<<endl;

       }

   }

3. Run your program again, but this time change the code so that the array is filled with random numbers between 1 and 100.  

   double alpha[50];

   for (int i=0;i<50;i++)

   {

       alpha[i]=rand()%101;

   }

   for (int i=0;i<50;i++)

   {

       cout<<i+1<<". "<<alpha[i]<<" ";

       if (((i+1)%10)==0)

       {

           cout<<endl;

       }

   }

4. Write the code that computes and prints the average of elements of the array.  

   double alpha[50],temp=0;

   for (int i=0;i<50;i++)

   {

       alpha[i]=rand()%101;

       temp+=alpha[i];

   }

   cout<<"Average :"<<(temp/50);

5. Write the code that that prints out how many of the elements are EXACTLY equal to 100.

   double alpha[50],temp=0;

   for (int i=0;i<50;i++)

   {

       alpha[i]=rand()%101;

       if(alpha[i]==100)

       {

           temp++;

       }

   }

   cout<<"Elements Exacctly 100 :"<<temp;

Please note:  If you put  each of above code to the place below comment  it will run perfectly after compiling

#include <iostream>

using namespace std;

int main()

{

   // If you put  each of above code here it will run perfectly after compiling

   return 0;

}

8 0
3 years ago
(photoshop cc)
iren2701 [21]
Black Point<span> Compensation option </span>controls whether to adjust for differences in black points when converting<span> colors </span>between color spaces<span>.

A is the answer :)

</span>
5 0
3 years ago
Which of the following processes should Angel use to merge cells A1:D4 to create a title?
podryga [215]

Answer:

Highlight cells A1:D4, right-click and select Format Cells, click Alignment, and choose the Merge cells option.

Explanation:

We merge cells with the help of following methods.

<u>Method 1  </u>

  1. Highlight cells A1:D4
  2. click on the Home tab
  3. click on the <u>Merge and Center</u> icon in the Alignment group

1st method is not given in options of question.

<u>Method 2</u>

  1. Highlight cells A1:D4
  2. right-click and select Format Cells
  3. click Alignment
  4. choose the Merge cells option

<em>2nd method is matching with </em><em><u>option D. </u></em><em>So, Option D is the answer.</em>

<u />

6 0
3 years ago
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