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3 years ago

Does the USA share the F-22 raptor technology with anyone else?True or False?

Computers and Technology

2 answers:

Brilliant_brown [7]3 years ago

8 0

Answer:

False

Okay now I have to go to my school--

Natali5045456 [20]3 years ago

8 0

Answer:

FALSE

Explanation:

False because They were going to but it got canceled because our USA military couldn't share it with anyone

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The term _____ best describes the level of technology skills needed in today’s business world.

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The answer is fluency.

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Read 2 more answers

Which of the following galaxy types is most likely to be clearly identifiable, regardless of orientation? SBc

Reil [10]

Answer:

The most likely galaxy type to be identifiable regardless of orientation is: Irr

Explanation:

The Irr galaxies don't have a discernable or usual shape; that is why it is relatively easy to identify.

When we talk about E type galaxies, this statement proves itself by the way the cumulus of stars compounds the galaxy. The elliptical galaxies have the form of ellipses, with a reasonable distribution of stars. The degree of eccentricity is the number that complements the E letter; that's why E0 galaxies are almost spherical, while E7 is considerably elongated.

SBc, SBa galaxies are spiral; this means it can be flat in some angles difficulting their identification process; in this case, the last letter means the way the arms display their form, with "c" having a vague form and "a" well-defined arms. That's why in some angles can be mistreated as another type of galaxy.

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3 years ago

given an array of integers a, your task is to count the number of pairs i and j (where 0 ≤ i < j < a.length), such that a[

Nimfa-mama [501]

Using the knowledge of computational language in C++ it is possible to write a code that given an array of integers a, your task is to count the number of pairs i and j.

<h3>Writting the code:</h3>

// C++ program for the above approach

#include <bits/stdc++.h>

using namespace std;

// Function to find the count required pairs

void getPairs(int arr[], int N, int K)

{

// Stores count of pairs

int count = 0;

// Traverse the array

for (int i = 0; i < N; i++) {

for (int j = i + 1; j < N; j++) {

// Check if the condition

// is satisfied or not

if (arr[i] > K * arr[j])

count++;

}

cout << count;

}

// Driver Code

int main()

{

int arr[] = { 5, 6, 2, 5 };

int N = sizeof(arr) / sizeof(arr[0]);

int K = 2;

// Function Call

getPairs(arr, N, K);

return 0;

}

See more about C++ code at brainly.com/question/17544466

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1 year ago

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Explanation:

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3 years ago